The total energy of particle, executing simple harmonic motion is
∝ x
∝ x2
independent of x
independent of x
C.
independent of x
In simple harmonic motion when a particle is displaced to a position from its mean position, then its kinetic energy gets converted into potential energy and vice-versa. Hence, total energy of a particle remains constant or the total energy in simple harmonic motion does not depend on displacement x.
A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0. An external force F(t) proportional to cosωt (ω≠ω0) is applied to the oscillator. The time displacement of the oscillator will be proportional to
In forced oscillation of a particle the amplitude is maximum for a frequency ω1 of the force, while the energy is maximum for a frequency ω2 of the force, then
ω1 = ω2
ω1 > ω2
ω1 < ω2 when damping is small and ω1 > ω2 when damping is large
ω1 < ω2 when damping is small and ω1 > ω2 when damping is large
A massless spring of length l and spring constant k is placed vertically on a table. A ball of mass m is just kept on top of the spring. The maximum velocity of the ball is
A particle of mass 3 kg, attached to a spring with force constant 48 N/m execute simple harmonic motion on a frictionless horizontal surface. The time period of oscillation of the particle, in seconds, is
The position and velocity of a particle executing simple harmonic motion at t = 0 are given by 3 cm/s and 8 cm/s respectively. If the angular frequency of the particle is 2 rad/s, then the amplitude of oscillation, in centimeters, is
3
4
5
6
A simple harmonic motion is represented by x(t) = sin2 ωt − 2 cos2 ωt. The angular frequency of oscillation is given by
ω
2ω
4ω
ω/2
Two equal masses hung from two massless springs of spring constants k1 and k2. They have equal maximum velocity when executing simple harmonic motion. The ratio of their amplitudes is
The simple harmonic motion of a particle is given by x = a sin 2t. Then, the location of the particle from its mean position at a time 1/8th of a second is
a
The time-period of a simple pendulum of length m suspended in a car moving with uniform acceleration of 5ms-2 in a horizontal straight road is (g = 10 ms-2)