A-pendulum suspended from the ceiling of a train has a period T when the train is at rest. When the train accelerates with a uniform acceleration a, the period of oscillation will
increase
decrease
remain unaffected
become infinite
The motion of a particle executing SHM is given by x = 0.01sin1O0(t + 0.05), where x is in metre and t in second. The time period of
motion (in second) is
0.01
0.02
0.1
0.2
A simple pendulum has a length l and the mass of the bob is m. The bob is given a charge q coulomb. The pendulum is suspended between the vertical plates of a charged parallel plate capacitor. If E is the electric field strength between the plates, the time period of the pendulum is given by
The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation is
20π s
2π s
200 s
A particle of mass 10 g is describing SHM along a straight line with a period of 2 s and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is
3.75 π2 erg
375 π2 erg
0.375 π2 erg
37.5 π2 erg
The angular amplitude of a simple pendulum is θ0 The maximum tension in its string will be
mg(1 - θ0)
mg(1 + θ0)
mg(1 - )
mg(1 + )
The graph between velocity and displacement of a particle, executing SHM is:
a straight line
a parabola
a hyperbola
an ellipse
A body executing SHM has its velocity 10 cm/s and 7 cm/s when its displacements from the mean position are 3 cm and 4 cm respectively. The length of the path is :
10 cm
9.5 cm
4 cm
11.36 cm
A particle executing simple harmonic motion has a time period of 4 sec. After how much interval of time from t = 0 will its displacement be half of its amplitude :
1/3 sec
1/2 sec
2/3 sec
1/6 sec
A.
1/3 sec
Time period T = 4 sec
From the equation of SHM
Here y = a/2
t = 1/3 sec
A particle is executing the motion x = a cos (ωt - θ). The maximum velocity of the particle is :
aω cosθ
aω
aω sinθ
none of these