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 Multiple Choice QuestionsMultiple Choice Questions

281.

Assertion:  A double convex lens ( μ = 1.5 ) has focal length 10 cm. When the lens is immersed in water ( μ = 4/3 ) its focal length becomes 77 cm.

Reason:  1f = μg - μwμw1R1 - 1R2

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


282.

The camera lens has an aperture off and the exposure time is ( 1/60) s. What will be the new exposure time if the aperture become 1.4 f ?

  • 142

  • 156

  • 172

  • 131


283.

A point source is kept at a distance of   1000 m has an illumination I. To change the illumination to 161 the new distance should become

  • 250 m

  • 500 m

  • 750 m

  • 800 m


284.

Assertion:  Goggles have zero power.

Reason: Radius of curvature of both sides of lens is same.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


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285.

Assertion:  Optical fibres are used for telecommunication.

Reason: Optical fibres are based on the phenomenon of total internal reflection.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


286.

In refraction, light waves are bent on passing from one medium to the second medium, because in the second medium

  • the frequency is different

  • the coefficient of elasticity is different

  • the speed is different

  • the amplitude is smaller


287.

A wire mesh consisting of very small squares is viewed at a distance of 8 cm through a magnifying converging lens of focal length 1O cm, kept close to the eye. The magnification produced by the lens is

  • 5

  • 8

  • 10

  • 20


288.

A lens is made of flint glass (refractive index= 1.5). When the lens is immersed in a liquid of refractive index 1.25, the focal length

  • increases by a factor of 1.25

  • increases by a factor of 2.5

  • increases by a factor of 1.2

  • decreases by a factor of 1.2


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289.

Assertion:  In optical fibre, the diameter of the core is kept small. 

Reason:  This smaller diameter of the core ensures that the fibre should have incident angle more than the critical angle required for total internal reflection.

  • If both assertion and reason are true and reason is the correct explanation of the assertion

  • If both assertion and reason are true but reason is not the correct explanation of the assertion

  • If assertion is true, but reason is false

  • Both assertion and reason are false statements


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290.

What should be the maximum acceptance angle at the air-core interface of an optical fibre if  n1  and  n2 are the refractive indices of the core and the cladding, respectively?

  • sin-1( n2/n1 )

  • sin-1n1 2 - n2 2

  • tan-1 n2n1

  • tan-1 n1n2


B.

sin-1n1 2 - n2 2

'i' is max acceptance angle (incidence angle ) air core interface which make  'r' as refraction angle  ( 90° - r ) as critical angle at core cladding interface making refraction angle 90°

angle 1 is i, angle 2 is r, angle 3 is r , angle is 4 is  (90° - r ), angle 5 is 90°

At air core interface

By snell's law

     n sin i = nsin r

For air  n  = 1

sin i = n1 sin r

at core cladding interface

    n1 sin (90° - r ) = n2 sin 90°

     n1 cosr = n2n1

         sin i = 1 - cos2 r

                 = n1 2 - n2 2n1 

        sini = n1 sinr

              = n1 2 - n2 2

Acceptance angle = arc sinn1 2 - n2 2

So total internal reflection angle has to be less than Acceptance angle.


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