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 Multiple Choice QuestionsMultiple Choice Questions

211.

Resolving power of human eye is

  • 0.1"

  • 1"

  • 0.1'

  • 1'


212.

If distance between light source and screen is doubled, then intensity of light will become

  • half

  • double

  • remains same

  • 1/4 th


213.

When the distance between slits of Young's double slit experiment is reduced to half then the fringe middle will become

  • constant

  • four times

  • two times

  • half


214.

A beam of light after reflection on a plane mirror forms a real image. The beam is

  • convergent

  • divergent

  • parallel to axis

  • parallel but not to axis of mirror


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215.

In Young's double slit experiment, monochromatic light of wavelength 600 nm illuminates  the pair of slits and produces an interference pattern in which two consecutive bright fringes are separated by 10 mm. Another source of monochromatic light produces the interference pattern in which of the two consecutive bright fringes are separated by 8 mm. The wavelength of light from the second source is

  • 448 nm

  • 450 nm

  • 480 nm

  • 580 nm


216.

Light passes through two polaroids P1 and P2 with pass axis of P2 making an angle θ with the pass axis of P1.  That value of θ for which the intensity of emergent light is zero.

  • 45°

  • 90°

  • 30°

  • 60°


217.

If the angle between the axis of polarizer and the analyser is 45 degree, the ratio of the intensities of original light and the transmitted light after passing through the analyser is

  • 2 : 1

  • 1 : 2

  • 2 : 3

  • 1 : 1


218.

A beam of monochromatic light is incident on one face of an equilateral prism. The angle of incidence is 55°. If the angle of emergence is 46°, then the angle of minimum deviation δmwill be

  • > 41°

  • < 41°

  • = 41°

  • ≥ 41°


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219.

Mark the wrong statement regarding polarisation of light

  • The vibrations in a plane polarised light are perpendicular to the plane of polarisation

  • If a polarised light of intensity l0 , is passed through an analyser the intensity of light transmitted is I = l0 cos2 θ

  • Polarisation is the property of longitudinal wave

  • Tangent of polarising angle is equal to the refractive index of medium upon which the light is incident


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220.

The blue colour of sky is explained by

  • reflection

  • scattering

  • polarisation

  • refraction


B.

scattering

Blue colour of the sky is explained by the scattering phenomena of light. From Rayleigh's law, the intensity of light is related to its wavelength as I ∝ 1λ4. So, the shorter waves are scattered with more intensity. In visible light, violet and blue light have minimum wavelength. Out of these two, the blue colour is more intense.


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