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 Multiple Choice QuestionsMultiple Choice Questions

61.

When a stationary wave is formed then its frequency is

  • same as that of the individual waves

  • twice that of the individual waves

  • half that of the individual waves

  • 2  that of the individual waves


62.

A person carrying a whistle emitting continuously a note of 272 Hz is running towards a reflecting surface with a speed of 18 km/h. The speed of sound in air is 345 ms-1. The number of beats heard by him is

  • 4

  • 6

  • 8

  • 3


63.

The equation of a transverse wave travelling along positive X-axis with amplitude 0.2 m, velocity 360 m/sec and wavelength 60 m can be written as

  • y = 0.2 sin π 6t + x60

  • y = 0.2 sin π 6t - x60

  • y = 0.2 sin 2π 6t - x60

  • y = 0.2 sin 2π 6t + x60


64.

If vm is the velocity of sound in moist air, vd is the velocity of sound in dry air, under identical conditions of pressure and temperature.

  • vm < vd

  • vm > vd

  • vmvd = 1

  • vm = vd


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65.

If T is the reverberation time of an auditorium ofvolume V, then

  • T ∝ V2

  • T ∝ V

  • T  1V

  • T  1V2


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66.

Two wires are fixed in a sonometer. Their tensions are in the ratio 8 : 1. The lengths are in the ratio 36 :35. The diameters are in the ratio 4 : 1. Densities of the materials are in the ratio 1 :2. If the higher frequency in the setting is 360 Hz, the beat frequency when the two wires are sounded together, is

  • 8

  • 5

  • 10

  • 6


C.

10

Frequency of sonometer wire is given by

  n = 12l Tm = 12l Tπr2ρ       n1 = 12l1 T1πr12ρ1                                    ....... (i)       n2 = 12l2 T2πr22ρ2                                    ....... (ii)  n1n2 = l2l1 T1T2 × r22r12 × ρ2ρ1       n1n2 = 3536 81 × 116 × 21 n1 < n2  and n2 = 360Therefore,            n = 360 × 3536 ,  n1 = 350 Hz

So, number of beats produced = n1 − n2

        = 360 − 350

        = 10


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67.

A sound source is moving towards stationary listener with 110th of the speed of sound. The ratio of apparent to real frequency is

  • 9102

  • 109

  • 1110

  • 11102


68.

If v is the speed of sound in air, then the shortest length of the closed pipe which resonates to a frequency n, is

  • v2n

  • v4n

  • 4nv

  • 2nv


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69.

Cavitation is a special application property exhibited only by

  • ultrasonics

  • electromagnetic waves

  • audible sound

  • infrasonics


70.

Waves that cannot be polarised are

  • electromagnetic waves

  • light waves

  • longitudinal waves

  • transverse waves


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