If 999x + 888y = 1332 and 888x + 999y = 555, then is equal to
5
7
8
8
B.
7
We have,
999x + 888y = 1332
and 888x + 999y = 555
On dividing both equation by 111,
we get
9x + 8y = 12 ...(i)
8x + 9y = 5 ...(ii)
On multiplying Eq. (i) by 9 and Eq. (ii) by 8, then subtract Eq.(ii) from Eq. (i), we get,
81x + 72y = 108
64x + 72y = -40
17x = 68
Put the value of x in Eq. (i) we get,
A man loses of his money and after spending 80% of the remainder, he is left with ₹ 159. How much did he have at first?
₹ 500
₹ 800
₹ 1000
₹ 1000