An interior angle of a regular polygon is 5 times its exterior angle. Then the number of sides of the polygon is
14
16
12
18
The measure of an angle whose supplement is three times as large as its complement, is
60°
75°
30°
45°
D.
45°
Let the required angle be x°.
According to the question,
Supplement of x = 180° - x
Complement of x = 90° - x
According to the question,
180° - x = (90° - x) x 3
⟹ 180° - x = 270° - 3x
⟹ 3x - x = 270° - 180° = 90°
⟹ 2x = 90°, ⟹ x = 45°