In trapezium ABCD, AB || CD and AB = 2CD. Its diagonals intersect at O. If the area of ΔAOB = 84 cm2, then the area of ΔCOD is equal to
72 cm2
21 cm2
42 cm2
42 cm2
Quadrilateral ABCD is circumscribed about a circle. If the lengths of AB, BC and CD are 7 cm, 8.5 cm and 9.2 cm respectively, then the length ( in cm) of DA is
7.7
16.2
10.7
10.7
The area of an isosceles trapezium is 176 cm2 and the height is of the sum of its parallel sides. If the ratio of the length of the parallel sides is 4 : 7, then the length of a diagonal (in cm) is
28
√137
2√137
4√137
ABCD is a cyclic trapezium in which AD || BC. If ∠ABC = 70°, then ∠BCD is
110°
80°
70°
90°
Let Δ ABC and Δ ABD be on the same base AB and between the same parallels AB and CD. Then the relation between areas of Δ ABC and Δ ABD will be
Δ ABD = 1/3 Δ ABC
Δ ABD = 1/2 Δ ABC
Δ ABC = 1/2 Δ ABD
Δ ABC = 1/3 Δ ABD
D.
Δ ABC = 1/3 Δ ABD
As we all know that, Triangles on the same base and between same parallels are always equal in area
∴ Δ ABC = Δ ABD
ABCD is a trapezium in which AD || BC and AB = DC = 10 m. Then the distance of AD from BC is
10√2 m
4√2 m
5√2 m
6√2 m
In a cyclic quadrilateral ABCD, the side AB is extended to a point X. If ∠XBC = 82° and ∠ADB = 47°, then the value of ∠BDC is
40°
35°
30°
25°
Three angles of a quadrilateral are 60°, 90° and 100°. Then the fourth angle of the quadrilateral is:
95°
100°
110°
115°
The diagonals of AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that
AP . CP = BP. DP
AP. BP = CP. DP
AP. CD = AB. CP
BP. AB = CD. CP