ABCD is a rhombus. AB is produced to F and B produced to E such that AB = AE = BF. Then,
ED2 + CF2 = EF2
ED || CF
ED > CF
ABCD is a cyclic quadrilateral. AB and DC are produced to meet at P. If ∠ADC = 60°, then the ∠PBC + ∠PCB is
130°
150°
155°
180°
ABCD is a cyclic trapezium with AB || DC and AB a diameter of the circle. If ∠CAB = 30°, then ∠ADC is
60°
120°
150°
30°
B.
120°
Now, in Δ ACB,
As ABCD is a cyclic trapezium,
One of the four angles of a rhombus is 60°. If the length of each side of the rhombus is 8 cm, then the length of the longer diagonal is
8√3 cm
8 cm
4√3 cm
8 /√3 cm