A point D is taken from the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then
AB2 + CD2 = BC2 + AD2
CD2 + BD2 = 2 AD2
AB2 + AC2 = 2AD2
AB2 + AC2 = 2AD2
An isosceles triangle ABC is right-angled at B. D is a point inside the triangle ABC. P and Q are the feet of the perpendiculars drawn from D on the sides AB and AC respectively of ΔABC. If AP = a cm, AQ = b cm and ∠BAD = 15°, sin 75° =
D and E are two points on the sides AC and BC respectively of Δ ABC such that DE = 18 cm, CE = 5 cm and ∠DEC = 90°, If tan ∠ABC = 3.6, then AC : CD =
BC : 2 CE
2 CE : BC
2 BC : CE
2 BC : CE
D is a point on the side BC of a triangle ABC such that . E is a point on AD for which AE : ED = 5 : 1. If
and then
then
30°
45°
60°
40°
In ΔABC, P and Q are the middle points of the sides AB and AC respectively. R is a point on the segment PQ such that PR : RQ = 1 : 2. If PR = 2cm, the BC =
4 cm
2 cm
12 cm
12 cm
The angles of a triangle are in Arithmetic Progression. The ratio of the least angle in degrees to the number of radians in the greatest angle is . The angles in degrees are
30°, 60°, 90°
35°, 55°, 90°
40°, 50°, 90°
40°, 50°, 90°
A.
30°, 60°, 90°
Let the angles of a triangle
According to the question,
∴ Angles of a triangle:
a - d = 60° - 30° = 30°
a = 60°
a + d = 60° + 30° = 90°
If the incentre of an equilateral triangle lies inside the triangle and its radius is 3 cm, then the side of the equilateral triangle is
Suppose ΔABC be a right-angled triangle where and
If Δ ABC = 40 cm2, ΔACD = 10 cm2 and
then the length of BC is
12 cm
18 cm
4 cm
4 cm
In ΔABC, D and E are points on AB and AC respectively such that DE || BC and DE divides the ΔABC into two parts of equal areas. Then ratio of AD and BD is
1 : 1