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Mensuration - Volume and Surface Areas

Multiple Choice Questions

111.
A conical flask is full of water. The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is

$straight h over 2 straight m squared$

$fraction numerator 2 straight h over denominator straight m end fraction$

$fraction numerator straight h over denominator 3 straight m squared end fraction$

$fraction numerator straight m over denominator 2 straight h end fraction$

$fraction numerator straight h over denominator 3 straight m squared end fraction$

Volume of conical flask = Volume of water
$equals space 1 third πr squared straight h$
Now, the water is poured into the cylindrical flask.
Therefore, According to the question,
Volume of cylinder = Volume of water
$rightwards double arrow space space straight pi left parenthesis mr right parenthesis squared space cross times space Height space equals space 1 third πr squared straight h therefore space space space space space Height space space equals space fraction numerator straight h over denominator 3 straight m squared end fraction$

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112.

The curved surface area and the total surface area of a cylinder are in the ratio 1 : 2. If the total surface area of the right cylinder is 616 cm², then its volume is

1632 cm³
1078 cm³
1232 cm³
1848 cm³

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Previous Year Papers

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Multiple Choice Questions

111. A conical flask is full of water. The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is