The curved surface area and the total surface area of a cylinder

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 Multiple Choice QuestionsMultiple Choice Questions

111.

A conical flask is full of water. The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is

  • straight h over 2 straight m squared

  • fraction numerator 2 straight h over denominator straight m end fraction

  • fraction numerator straight h over denominator 3 straight m squared end fraction

  • fraction numerator straight m over denominator 2 straight h end fraction

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112.

The curved surface area and the total surface area of a cylinder are in the ratio 1 : 2. If the total surface area of the right cylinder is 616 cm2, then its volume is

  • 1632 cm3

  • 1078 cm3

  • 1232 cm3

  • 1848 cm3


B.

1078 cm3

Curved surface area of cylinder:
                   equals space space space 2 πrh space cm squared
Total surface area of cylinder:
                 space equals space 2 πr left parenthesis straight h space plus space straight r right parenthesis space cm squared
Now, according to the question,
  rightwards double arrow space space space space space fraction numerator 2 πrh over denominator 2 πr left parenthesis straight h plus space straight r right parenthesis end fraction space equals space 1 half
rightwards double arrow space space space space fraction numerator straight h over denominator straight h plus straight r end fraction space equals space 1 half
rightwards double arrow space space space 2 straight h space equals space straight h space plus space straight r
rightwards double arrow space space space space straight h space equals space straight r

Now, Total surface area = 616 cm2
rightwards double arrow space space space space 2 πr left parenthesis straight h space plus space straight r right parenthesis space equals space 616
rightwards double arrow space space space space 2 πr left parenthesis straight r plus space straight r right parenthesis space equals space space 616 space space space space space space space space space space left parenthesis as space straight h space equals space straight r right parenthesis
rightwards double arrow space space space space 2 πr left parenthesis 2 straight r right parenthesis space equals space 616
rightwards double arrow space space space space space space 4 πr squared space equals space space 616
therefore space space space space space space space space space space space space space space space space space straight r space equals space square root of fraction numerator 616 over denominator 4 straight pi end fraction end root space equals space square root of fraction numerator 616 space cross times space 7 over denominator 4 space cross times space 22 end fraction end root space equals space square root of 7 space cross times space 7 end root space equals space 7 space cm

∴       Volume
                equals space πr squared straight h
equals space 22 over 7 space cross times space open parentheses 7 space cross times 7 close parentheses space cross times space 7 space equals space 1078 space cm squared

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