Multiple Choice QuestionsThe sum of the areas of the 10 squares, the lengths of whose sides are 20 cm, 21 cm,....29 cm respectively is
6085 cm2
8555 cm2
2470 cm2
2470 cm2
A number, when divided successively by 4, 5 and 6 leaves remainders 2, 3 and 4 respectively. The least such number is
50
53
56
58
A number when divided by 361 gives a remainder 47. If the same number is divided by 19, the remainder obtained is
3
8
9
9
The unit digit in the product (2467)153 x (341)172 is
7
8
4
4
A.
7
Unit digit in (2467)153
Cancel all (power digits except unit & ten's digit) and take it power to unit digit
Thus, we can write (7)53,
Now divide power 53 by 4, we get remainder 1. Make this remainder the power of (7) i.e. (7)1 = 7
∴ Unit digit in (2467)153 = 7 ...(i)
Similarly,
(341)72 = (1)72 on dividing power 72 by 4 we get remainder zero, when remainder is zero, take power 4
i.e. (1)4 = 1
∴ Unit digit in (341)72 = 1 ...(ii)
∴ Unit digit (2467)153 x (341)72 = 7 x 1 = 7
If the sum of the digits of a three-digit number is subtracted from that number, then it will always be divisible by
3 only
9 only
Both 3 and 9
Both 3 and 9
The sum of the cubes of two numbers in the ratio 3 : 4 is 5824. The sum of the number is
(5824)1/3
28
24
24
What least value must be assigned to '*' so that the number 451*603 is exactly divisible by 9?
7
8
5
5
Switch
, then the value of U1 + U2 + U3 + U4 + U5
