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In an examination, a student score 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly is

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42.
Find a number, one-seventh of which exceeds its eleventh part by 100.

1925

1825

1540

1340

1925

Let the number be x.
According to the question,
$straight x space cross times space 1 over 7 space minus space straight x over 11 space equals space 100 rightwards double arrow space space fraction numerator 11 straight x minus 7 straight x over denominator 77 end fraction space equals space 100 rightwards double arrow space space space 4 straight x space equals space 77 space cross times space 100 rightwards double arrow space space space space straight x space equals space fraction numerator 77 space cross times space 100 over denominator 4 end fraction rightwards double arrow space space space straight x space equals space 1925$

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43.

If $9 square root of straight x space equals space square root of 12 space plus space square root of 147 comma$ then x = ?

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44.

The value of $3 plus fraction numerator 1 over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style 1 third end style end fraction end style end fraction$ is

$40 over 11$
$43 over 11$
$46 over 11$
$41 over 11$

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45.

The value of $fraction numerator left parenthesis 3.2 right parenthesis cubed minus 0.008 over denominator left parenthesis 3.2 right parenthesis squared space plus space 0.64 space plus space 0.04 end fraction$ is

0
2.994
3.208
3

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46.

Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is

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47.

If $2 plus straight x space square root of 3 space equals space fraction numerator 1 over denominator 2 plus square root of 3 end fraction comma space$ then the simplest value of x is

1
-1
-2
2

48.

If $fraction numerator open square brackets 2 open parentheses begin display style fraction numerator 4 straight x over denominator 5 end fraction end style minus begin display style 3 over 4 end style close parentheses close square brackets over denominator 3 minus begin display style 5 over 3 end style end fraction space equals space minus 1 over 6 comma$ then the value of x is:

$4 over 15$
$negative 15 over 4$
$negative 4 over 15$
$15 over 4$

49.

If $fraction numerator 2 straight x over denominator 3 end fraction minus fraction numerator open square brackets 5 open parentheses begin display style fraction numerator 4 straight x over denominator 5 end fraction end style minus begin display style 4 over 3 end style close parentheses close square brackets over denominator 2 end fraction space equals space 1 third comma$ then what is the value of x?