A car driver leaves Bangalore at 8.30 A.M. and expects to reach

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21.

A man rows upstream 36 km and downstream 48 km taking 6 hours each time. The speed of the current is

  • 0.5 kmph

  • 2 kmph

  • 1 kmph

  • 1 kmph

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22.

A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at the rate 4 kmph and partly on bicycle at the rate 9 kmph. The distance travelled on foot is

  • 16 km

  • 14 km

  • 17 km

  • 17 km

279 Views

23.

The distance between 2 places R and S is 42 km. Anita starts from R with a uniform speed of 4 km/h towards S and at the same time Romita starts from S towards R also with some uniform speed. They meet each other after 6 hours. The speed of Romita is

  • 18 km/hr

  • 3 km/hr

  • 20 km/hr

  • 20 km/hr

536 Views

24.

A boat takes half time in moving a certain distance downstream than upstream. The ratio of the speed of the boat in still water and that of the current is

  • 2 : 1

  • 1 : 2

  • 4 : 3

  • 4 : 3

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25.

A man travelled a distance of 80 km in 7 hrs partly on foot at the rate of 8 km per hour and partly on bicycle at 16 km per hour. The distance travelled on the foot is

  • 32 km

  • 48 km

  • 36 km

  • 36 km

311 Views

26.

A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?

  • 20 seconds

  • 15 seconds

  • 17 seconds

  • 17 seconds

291 Views

27.

A man is walking at a speed of 10 kmph. After every km, he takes a rest for 5 minutes. How much time will he take to cover a distance of 5 km?

  • 60 minutes

  • 50 minutes

  • 40 minutes

  • 40 minutes

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28.

A car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. At 10.30 he finds that he has covered only 40% of the distance. By how much he has to increase the speed of the car in order to keep up his schedule?

  • 45 km/hr

  • 40 km/hr

  • 35 km/hr

  • 35 km/hr


D.

35 km/hr

Distance covered by car in 2 hours i.e (8.30 AM. TO 10.30 AM)
 equals space fraction numerator 300 space cross times space 40 over denominator 100 end fraction space equals space 120 space km
Remaining Distance = (300 -120) = 180 km
Remaining time = 4 - 2  = 2 hours
therefore space space Required space speed space equals space 180 over 2 space equals space 90 space kmph
Original speed of car = 120 over 2 space equals space 60 space kmph

∴  Required increase in speed  = (90 - 60)kmph = 30 kmph

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29.

If a distance of 50 m is covered in 1 minute, that 90 m in 2 minutes and 130 m in 3 minutes find the distance covered in 15 mintues.

  • 610 m

  • 750 m

  • 1000 m

  • 1000 m

327 Views

30.

A train goes from Ballygunge to Sealdah at an average speed of 20 km/hour and comes back at an average speed of 30 km/hour. The average speed of the train for the whole journey is

  • 27 km/hr

  • 26 km/hr

  • 25 km/hr

  • 25 km/hr

219 Views

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