Walking 6/7 of his usual speed, a man is 12 min too late. The usual time taken by him to cover that distance is
1 hr
1 h 12 min
1 h 15 min
1 h 20 min
A person travels 285 km in 6h. In the first part of the journey, he travels at 40 km/h by bus. In the second part, he travels at 55 km/h by train. The distance travelled by train is
165 km
615 km
561 km
156 km
A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is
4 : 1
1 : 4
2 : 1
1 : 2
Two cars are moving with speeds v1 and v2 towards a crossing along two roads. If their distances from the crossing be 40 m and 50 m at an instant of time, then they do not collide, if their speeds are such that
v1 : v2 ≠ 4 : 5
v1 : v2 ≠ 5 : 4
v1 : v2 ≠ 25 : 16
v1 : v2 ≠ 16 : 25
A, B and C walk 1 km in 5 min, 8 min and 10 min, respectively. C starts walking from a point, at a certain time, B starts from the same point 1 min later and A starts from the same point 2 min later than C. Then, A meet B and C at times
2 min, 3 min
2 min,
1 min, 2 min
C.
2 min,
Let the A meets B and C in X & Y min.
The distance covered by A in 5 min = 1 km
Then, the distance covered by A in 1 min = 1000/5 = 200 m.
The distance covered by B in 8 min = 1 km
Then, the distance covered by B in 1 min = 1000/8 = 125 m.
The distance covered by C in 10 min = 1 km
Then, the distance covered by C in 1 min = 1000/10 = 100 m.
According to the question,
Distance covered by C in (X + 2) min = the distance covered by in X min
Then, 100 (X + 2) = 200 X
100 X + 200 = 200 X
200 = 200 X – 100 X
100 X = 200
X = 200/100
X = 2 min.
Now, for A & B
Distance covered by B in (Y + 1) min = Distance covered by A in Y min
Then, 125( Y + 1) = 200 x Y
125 Y + 125 + 200 Y
125 = 200 Y – 125 Y
125 = 75 Y
Y = 125/75
Y = 5/ min.
Hence, A meets B and C at 2 min, 5/3 min.
A man rides at the rate of 18 km/h but stops for 6 min to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is
6 h
6 h 12 min
6 h 18 min
6 h 24 min
A farmer travelled a distance of 61 km in 9h. He travelled partly on foot at the rate of 4 km/h and partly on bicycle at the rate of 9 km/h. The distance travelled on foot is
14 km
17 km
15 km
16 km
Walking at the rate of 4 km/h a man covers certain distance in 2 h 45 min. Running at a speed of 16.5 km/h the man will cover the same distance in how many minutes?
45
50
40
35
A man travelled a distance of 60 km in 7 hours. He travelled partly on foot @ 6km/h and partly on bicycle @ 12 km/h. What is the distance (in km) travelled on foot?
15 km
9 km
48 km
24 km