If 2x - 1 < 5x +2 and 2x + 5 < 6 - 3x, then x can take which of the following values?
1
0
2
-2
B.
0
Putting x = 0
I. 2x - 1 < 5x + 2
⟹ 2 x 0 - 1 < 5 x 0 + 2
⟹ 0 - 1 < 0 + 2
⟹ -1 < 2
II. 2x + 5 < 6 - 3x
⟹ 2 x 0 + 5 < 6 - x 0
⟹ 0 + 5 < 6 - 0
⟹ 5 < 6
Clearly it satisfies the equation.