The batting average for 40 innings of a cricketer is 50 runs. Hi

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44.

The batting average for 40 innings of a cricketer is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is

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D.

172

Let the highest innings be of x runs.
So, the lowest innings shall be of (x - 172) runs.
∴  Total runs scored in 40 innings  = 40 x 50 = 2000 runs.
    Total runs scored in 38 innings  = 38 x 48 = 1824 runs
Now, 
According to the question,
     (x) + (x - 172) = 2000 - 1824 = 176
    ⟹  2x = 176 + 172 = 348
   therefore space space straight x space equals space 348 over 2 space equals space 174

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