P, Q R are the points so that PR = 3 cm, QR = 5 cm and PQ = 8 cm

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 Multiple Choice QuestionsMultiple Choice Questions

21.

X and Y are centres of circles of radii 9cm and 2 cm respectively, XY = 17cm. Z is the centre of a circle of radius r cm which touches the above circles externally. Given that angle XZY space equals space 90 degree comma the value of r is

  • 13 cm

  • 6 cm

  • 9 cm

  • 9 cm

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22.

AB and CD are two parallel chords of a circle of lengths 10 cm and 4 cm respectively. If the chords are on the same side of the centre and the distance between them is 3 cm, then the diameter of the circle is

  • 2 square root of 21 space cm
  • square root of 21 space cm
  • 2 square root of 29 space cm
  • 2 square root of 29 space cm
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23.

A chord of a circle is equal to its radius. The angle subtended by this chord at a point on the circumference is

  • 80°

  • 60°

  • 30°

  • 90°

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24.

ABC is a isosceles triangle inscribed in a circle. If AB = AC = 12√5 cm and BC = 24 cm then the radius of circle is

  • 10 cm

  • 15 cm

  • 12 cm

  • 14 cm

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25.

ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true?

  • BP = PC

  • BP > PC

  • BP < PC

  • BP ≥ PC

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26.

Let two chords AB and AC of the larger circle touch the smaller circle having same centre at X and Y. Then XY = ?

  • BC

  • 1/2 BC

  • 1/3 BC

  • 2/3 BC

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27.

A chord of length 39 cm is at a distance of 10.4 cm from the centre of a circle. Find the radius of the circle.

  • 19.5 cm (appr)

  • 22.1 cm (appr)

  • 28.6 cm (appr)

  • 28.6 cm (appr)

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28.

 

A chord of length 10 cm subtends an angle 120° at the centre of the circle. Distance of the chord from the centre is

  •  

    5 square root of 3

  •  

    fraction numerator 5 square root of 3 over denominator 2 end fraction

  •  

    fraction numerator 5 over denominator square root of 3 end fraction

  •  

    5

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29.

Length of a chord PQ of a circle with centre O is 4 cm. If the distance of PQ from the point O is 2 cm, then the length of the diameter is

  • 2√2

  • 3√2

  • 5√2

  • 4√2

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30.

P, Q R are the points so that PR = 3 cm, QR = 5 cm and PQ = 8 cm. The number of circle passing through the points P, Q, R is

  • 3

  • 2

  • 1

  • 1


D.

1

No circle can pass through these points as even it is not possible to make a triangle with sides, draw a rough diagram and check it out.

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