The product of two 2-digit number is 2160 and their H.C.F. is 12. The numbers are:
(12, 60)
(72, 30)
(36, 60)
(60, 72)
The least number that must be added to 8961 to make it exactly divisible by 84 is
27
57
141
107
The HCF and LCM of two numbers are 8 and 48 respectively. If one of the numbers is 24, then the other number is
48
36
24
16
D.
16
Product of the numbers = HCF X LCM
24 x second number = 8 x 48
The greatest number, which when subtracted from 5834, gives a number exactly divisible by each of 20, 28, 32 and 35, is
1120
4714
5200
5600
The LCM of three different numbers is 120. Which of the following cannot be their HCF?
8
12
24
35
The traffic lights at three different road crossings change after 24 s, 36 s and 54 s respectively. If they all change simultaneously at 10 : 15 : 00 am, then at what time will they again change simultanesouly?
10 : 16 : 54 am
10 : 18 : 36 am
10 : 17 : 02 am
10 : 22 : 12 am
What is the least number which when divided by 5, 6, 7, 8 gives the remainder 3 but is divisible by 9?
1463
1573
1683
1793
The HCF and LCM of two numbers are 12 and 924 respectively. Then the number of such pairs is
0
1
2
3
The least multiple of 13 which when divided by 4, 5, 6, 7 leaves remainder 3 in each case is
3780
3783
2520
2522