If , then the value of U1 + U2 + U3 + U4 + U5 from Quantitativ

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 Multiple Choice QuestionsMultiple Choice Questions

41.

The sum of the areas of the 10 squares, the lengths of whose sides are 20 cm, 21 cm,....29 cm respectively is

  • 6085 cm2

  • 8555 cm2

  • 2470 cm2

  • 2470 cm2

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42.

The missing term in the sequence
2, 3, 5, 7, 11, .......17, 19 is

  • 16

  • 15

  • 14

  • 14

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43.

The wrong number in the sequence
8, 13, 21, 32, 47, 63, 83 is

  • 32

  • 47

  • 63

  • 63

207 Views

44.

A number, when divided successively by 4, 5 and 6 leaves remainders 2, 3 and 4 respectively. The least such number is

  • 50

  • 53

  • 56

  • 58

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45.

A number when divided by 361 gives a remainder 47. If the same number is divided by 19, the remainder obtained is

  • 3

  • 8

  • 9

  • 9

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46.

The unit digit in the product (2467)153 x (341)172 is

  • 7

  • 8

  • 4

  • 4

263 Views

47.

If the sum of the digits of a three-digit number is subtracted from that number, then it will always be divisible by

  • 3 only

  • 9 only

  • Both 3 and 9

  • Both 3 and 9

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48.

If straight U subscript straight n space equals space 1 over straight n space minus space fraction numerator 1 over denominator straight n plus 1 end fraction, then the value of U1 + U2 + U3 + U4 + U5

  • 1 fourth
  • 5 over 6
  • 1 over 6
  • 1 over 6


B.

5 over 6
straight U subscript straight n space equals space 1 over straight n minus fraction numerator 1 over denominator straight n plus 1 end fraction
 U1 + U2 + U3 + U4 + U5
equals space open parentheses 1 minus fraction numerator 1 over denominator 1 plus 1 end fraction close parentheses space plus space open parentheses 1 half minus fraction numerator 1 over denominator 2 plus 1 end fraction close parentheses space plus space open parentheses 1 third minus fraction numerator 1 over denominator 3 plus 1 end fraction close parentheses space plus space open parentheses 1 fourth minus fraction numerator 1 over denominator 4 plus 1 end fraction close parentheses space plus space open parentheses 1 fifth minus fraction numerator 1 over denominator 5 plus 1 end fraction close parentheses
equals space open parentheses 1 minus 1 half close parentheses plus open parentheses 1 half minus 1 third close parentheses space plus space open parentheses 1 third minus 1 fourth close parentheses space plus space open parentheses 1 fourth minus 1 fifth close parentheses space plus open parentheses 1 fifth minus 1 over 6 close parentheses
equals space 1 half plus open parentheses fraction numerator 3 minus 2 over denominator 6 end fraction close parentheses space plus space open parentheses fraction numerator 4 minus 3 over denominator 12 end fraction close parentheses space plus open parentheses fraction numerator 5 minus 4 over denominator 20 end fraction close parentheses space plus space open parentheses fraction numerator 6 minus 5 over denominator 30 end fraction close parentheses
equals space 1 half plus 1 over 6 plus 1 over 12 plus 1 over 20 plus 1 over 30
equals space fraction numerator 30 plus 10 plus 5 plus 3 plus 2 over denominator 60 end fraction equals space 50 over 60 space equals space 5 over 6
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49.

The sum of the cubes of two numbers in the ratio 3 : 4 is 5824. The sum of the number is 

  • (5824)1/3

  • 28

  • 24

  • 24

138 Views

50.

What least value must be assigned to '*' so that the number 451*603 is exactly divisible by 9?

  • 7

  • 8

  • 5

  • 5

201 Views

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