The sum of 10 terms of the arithmetic series is 390. If the third term of the series is 19, find the first term:
3
5
7
7
What least value must be assigned to '*' so that the number 63576*2 is divisible by 8?
1
2
3
4
C.
3
A number is divisible by 8 if the number formed by last three digits is divisible by 8.
Go with option, Putting the option in *place to form number.
612, 622, 642 are not divisible, 632 is divisible by 8. Therefore '*' is 3
Which one of the following is the minimum value of the sum of two integers whose product is 24?
25
11
8
10
A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be
1
2
7
17
A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as
4
3
2
5