The remainder when 321 is divided by 5 is from Quantitative Apti

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 Multiple Choice QuestionsMultiple Choice Questions

51.

The sum of 10 terms of the arithmetic series is 390. If the third term of the series is 19, find the first term:

  • 3

  • 5

  • 7

  • 7

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52.

What least value must be assigned to '*' so that the number 63576*2 is divisible by 8?

  • 1

  • 2

  • 3

  • 4

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53.

Which one of the following is the minimum value of the sum of two integers whose product is 24?

  • 25

  • 11

  • 8

  • 10

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54.

Number of composite numbers lying between 67 and 101 is

  • 27

  • 24

  • 26

  • 23

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55.

The sum of the series
( 1 + 0.6 + 0.06 + 0.006 +  0.0006 + .....) is

  • 1 2 over 3

  • 1 1 third

  • 2 1 third

  • 2 2 over 3

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56.

A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be

  • 1

  • 2

  • 7

  • 17

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57.

The number 0.121212....... in the form straight p over straight q is equal to

  • 4 over 11

  • 2 over 11

  • 4 over 33

  • 2 over 33

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58.

A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as

  • 4

  • 3

  • 2

  • 5

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59.

The last digit of (1001)2008 +  1002 is

  • 0

  • 3

  • 4

  • 6

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60.

The remainder when 321 is divided by 5 is

  • 1

  • 2

  • 3

  • 4


C.

3

The unit digit of 321 is 3.
The remainder, when a number is divided by 5, always the unit digit itself. i .e. 3  is the right answer.

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