A certain number, when divided by 899, leaves the remainder 65. When the same number is divided by 31, the remainder is
3
4
1
2
A number x, when divided by 289 leaves 18 as the remainder. The same number when divided by 17 leaves y as a remainder. The value of y is
2
3
1
5
The fifth term of the sequence for which t1 = 1, t2 = 2 and tn+2 = tn + tn+1 is
5
10
6
8
If X and Y are the two digits of the number 347XY such that the number is completely divisible by 80, then what is the value of X + Y?
2
4
6
8
A.
2
If 347XY is divisible by 80 (i.e. 8 x 10), then Y = 0 is the only possibility.
A number is divisible by 8, if its last three digits are divisible by 8.
Last 3 digits i.e. 7X0 should be divisible by 8
So, X = 2
∴ X + Y = 2 + 0 = 2