If the number of items of a set A be n(A) = 40,  n(B) = 26 and

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1.

If the number of items of a set A be n(A) = 40,  n(B) = 26 and  n(A∩B) = 16, then n (A∪B) is equal to

  • 30

  • 40

  • 50

  • 50


C.

50

n(A ∪ B) = n(A) + n(B)  - n(A ∩ B)
             = 40 + 26 - 16 = 50

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