A man rides at the rate of 18 km/h but stops for 6 min to change

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 Multiple Choice QuestionsMultiple Choice Questions

61.

Walking 6/7 of his usual speed, a man is 12 min too late. The usual time taken by him to cover that distance is

  • 1 hr

  • 1 h 12 min

  • 1 h 15 min

  • 1 h 20 min

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62.

A person travels 285 km in 6h. In the first part of the journey, he travels at 40 km/h by bus. In the second part, he travels at 55 km/h by train. The distance travelled by train is

  • 165 km

  • 615 km

  • 561 km

  • 156 km

54 Views

63.

A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is

  • 4 : 1

  • 1 : 4

  • 2 : 1

  • 1 : 2

39 Views

64.

Two cars are moving with speeds v1 and v2 towards a crossing along two roads. If their distances from the crossing be 40 m and 50 m at an instant of time, then they do not collide, if their speeds are such that

  • v1 : v2 ≠  4 : 5

  • v1 : v2 ≠  5 : 4

  • v1 : v2 ≠  25 : 16

  • v1 : v2 ≠  16 : 25

36 Views

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65.

A, B and C walk 1 km in 5 min, 8 min and 10 min, respectively. C starts walking from a point, at a certain time, B starts from the same point 1 min later and A starts from the same point 2 min later than C. Then, A meet B and C at times

  • 2 min, 3 min

  • 4 over 3 min comma space space 3 space min

  • 2 min,  5 over 3 min

  • 1 min, 2 min

38 Views

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66.

A man rides at the rate of 18 km/h but stops for 6 min to change horses at the end of every 7th km. The time that he will take to cover a distance of 90 km is

  • 6 h

  • 6 h 12 min

  • 6 h 18 min

  • 6 h 24 min


B.

6 h 12 min

Rate of rider (Speed) = 18 km/h
Total distance  = 90 km
As he stops after every 7th km,
90 km = (12 x 7) + 6 km
i.e. he stops 12 times.
Time taken by rider in 12 times = 12 x 6 = 72 min
Real Time
equals space Distance over Time space equals space 90 over 18 space equals space 5 space straight h
∴  Require time taken
            = 5 h + 1 h 12 min = 6 h 12 min
   
        

49 Views

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67.

A farmer travelled a distance of 61 km in 9h. He travelled partly on foot at the rate of 4 km/h and partly on bicycle at the rate of 9 km/h. The distance travelled on foot is

  • 14 km

  • 17 km

  • 15 km

  • 16 km


68.

Walking at the rate of 4 km/h a man covers certain distance in 2 h 45 min. Running at a speed of 16.5 km/h the man will cover the same distance in how many minutes?

  • 45

  • 50

  • 40

  • 35


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69.

A man travelled a distance of 60 km in 7 hours. He travelled partly on foot @ 6km/h and partly on bicycle @ 12 km/h. What is the distance (in km) travelled on foot?

  • 15 km

  • 9 km

  • 48 km

  • 24 km


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