The polynomial ax3 + bx2 + x - 6 has (x+ 2) as a factor and leaves remainder 4 when divided by (x-2) Find the value of a and b.
a=2,b=0
a=1,b=1
a=0,b=2
a=7,b=5
A non-terminating but recurring decimal is
an integer
a natural number
a rational number
an irrational number
The factors of polynomial x3- 6x2 + 11x - 6 are
(x+1)(x+2)(x-3)
(x-1)(x+2)(x-3)
(x-1)(x-2)(x-3)
(x-1)(x-2)(x+3)
If , then the values of x are
1,-2
-1,-2
0,1
2,-1
D.
2,-1
put 3x=y....(1)
If
Then
also,
then, y=9
From Equation 1,
therefore x=-1
also 3x = 9
3x = 32
therefore x=2
If a, a + 2, a + 4 are prime numbers, then the number of values of a is
One
two
three
more than three