Chemical Bonding and Molecular Structure

The number of anti-boinding electron present in O${}_2^{+}$ molecular ion is

• 8

• 6

• 5

• 4

The pair of compounds having identical shapes for their molecules is

• CH₄, SF₄

• BCl₃, ClF₃

• XeF₂, ZnCl₂

• SO₂, CO₂

The correct arrangement for the ions in the increasing order of their radii is

• Na⁺, Cl^-, Ca²⁺

• Ca²⁺, K⁺, S^2-

• Na⁺, Al³⁺, Be²⁺

• Cl^-, F^-, S^2-

The correct arrangement of the species in the decreasing order of the bond length between carbon and oxygen in them is

• CO, CO₂, HCO${}_2^{-}$, CO${}_3^{2-}$

• CO₂,CO, CO${}_3^{2-}$, HCHO${}_2^{-}$

• CO${}_3^{2-}$, HCO${}_2^{-}$, CO₂, CO

• CO, CO${}_3^{2-}$, CO₂, HCO${}_2^{-}$

A correct statement is

• [Co(NH₃)₆]²⁺ is paramagnetic

• [MnBr₄]^2- is tetrahedral

• [CoBr₂(en)₂]^- exhibits linkage isomerism

• [Ni(NH₃)₆]²⁺ is an inner orbital complex

Which one of the following conversion results in the change of hybridisation and geometry?

• CH₄ to C₂H₂

• NH₃ to N⁺H₄

• BF₃ to BF${}_4^{-}$

• H₂O to H₃O⁺

If the bond energies of H-H, Br-Br and H-Br are 433, 192 and 364 kJ mol^-1 respectively, then $∆$H° for the reaction-

H₂ (g) + Br₂ (g) → 2HBr (g) is

• -261 kJ

• +103 kJ

• +261 kJ

• -103 kJ

The shape of XeF₆ is

• square planar

• distorted octahedral

• square pyramidal

• pyramidal

CO is a stronger ligand than Cl^-, because

• CO is a neutral molecule

• CO has $\mathrm{\pi }$-bonds

• CO is poisonous

• CO is more reactive

Which of the following sequence is correct regarding field strength of ligands as per spectrochemical series?

• SCN^- < F^- < CN^- < CO

• F^- < SCN^- < CN^- < CO

• CN^- < F^- < CO < SCN^-

• SCN^- < CO < F^- < CN^-