Multiple Choice QuestionsWhich of the following is a favourable factor for cation formation?
High electronegativity
High electron affinity
Low ionisation potential
Smaller atomic size
Observe the following statements :
I. The physical and chemical properties of elements are periodic functions of their electronic configuration.
II. Electronegativity of fluorine is less than the electronegativity of chlorine.
III. Electropositive nature decreases from top to bottom in a group.
The correct answer is :
I, II and III are correct
only I is correct
only I and II is correct
only II and III are correct
The correct order of reducing abilities of hydrides of V group elements is
NH3 < PH3 < AsH3 < SbH3 < BiH3
NH3 > PH3 > AsH3 > SbH3 > BiH3
NH3 < PH3 > AsH3 > SbH3 > BiH3
SbH3 > BiH3 > AsH3 > NH3 > PH3
A radioactive substance 88X228 (IIA) emit 3α and 3β particles to form "Y". To which group of long form of the periodic table does "Y" belong ?
IVA
VA
VIA
VIIA
Which one of the following order is correct for the first ionisation energies of the elements?
B < Be < N < O
Be < B < N < O
B < Be < O < N
B < O < Be < N
Which one of the following is correct order of second ionisation potential of Na, Ne, Mg and Al?
Al < Na < Mg < Ne
Ne < Al < Na < Mg
Mg < Al < Ne < Na
Na < Mg < Ne < Al
C.
Mg < Al < Ne < Na
The electronic configuration of Na, Ne, Mg and Al afterthe removal of an electron is as-
Na+ : 1s2, 2s2, 2p6
Ne+ : 1s2, 2s2, 2p5
Mg+ : 1s2, 2s2, 2p6, 3s2
Al+ : 1s2, 2s2, 2p6, 3s2
The ionisation energy decreases as the size of the atom/ ion increases. Further ionisation
energy increases with increase in nuclear charge.
Since, Na+ gives a stable electronic configuration hence its IE2 is highest among the given species and therefore the correct order of their IE2 is
Mg < Al < Ne < Na
Identify the most acidic oxide among the following oxides based on their reaction.
SO3
P4O10
Cl2O7
N2O5
Match the following:
| List - I | List - II |
| A. Rubidium | 1. Germanium |
| B. Platinum | 2. Radioactive chalcogen |
| C. Eka-silicon | 3. s-block element |
| D. Polonium | 4. Atomic number 78 |
A - 4; B - 3; C - 2; D - 1
A - 3; B - 4; C - 1; D - 2
A - 2; B - 1; C - 4; D - 3
A - 4; B - 3; C - 1; D - 2
Identify the correct statement.
Lead forms compounds in +2 oxidation state due to inert pair effect.
All halogens show only negative oxidation state.
Catenation property increases from boron to oxygen.
Oxadation state of oxygen is - 1 in ozonides.
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