In the modern periodic table the place of the element with atomic number 31 is in
s- block
d-block
p- block
f- block
The correct sequence of decrease in size of the following species is
I> I+> I-
I> I-> I+
I+> I-> I
I-> I> I+
The decreasing order of the ionisation potential in the following elements is
Ne> Cl>P> S>Al>Mg
Ne> Cl> P> S> Mg> Al
Ne> Cl> S>P> Mg> Al
Ne> Cl> S>P> Al> Mg
Which of the following represents the electronic configuration of the most electropositive element?
[He]2s1
[He]2s2
[Xe]6s1
[Xe]2s2
C.
[Xe]6s1
Elements having lower value of ionisation potential are called electropositive elements. Ionisation potential of element increases from left to right in a period and decreases from top to bottom in group. So, element belonging to higher period of group-IA most electropositive.
In the following, the element with the highest electropositivity is
copper
cesium
barium
chromium
The number of unpaired electrons is maximum in (Atomic number Ti = 22; V= 23; Cr =24; Fe=26)
Fe
Cr
Ti
V
On moving from left to right in the second period along the periodic table the gram atomic volume of the element
increases with constant velocity
remains unchanged
first increases and then decreases
decreases
Which of the following is the correct order of the size of iodine species?
I > I- > I+
I- > I > I+
I+ > I > I-
I > I+ > I-