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 Multiple Choice QuestionsMultiple Choice Questions

71.

If α and β  B are the roots of the quadratic equation is, x2 + ax + b = 0, (b 0), then the quadratic equation whose roots are α - 1β, β - 1α, is

  • ax2 + a(b - 1)x + (a - 1)2 = 0

  • bx2 + a(b - 1)x + (b - 1)2 = 0

  • x2 + ax + b = 0

  • abx2 + bx + a = 0


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72.

If α and β are the roots of the quadratic equation ax2 + bx + c = 0 and 3b2 = 16ac, then

  • α = 4β or β = 4α

  • α = - 4β or β = - 4α

  • α = 3β or β = 3α

  • α = - 3β or β = - 3α


C.

α = 3β or β = 3α

Given that, (α, β) are roots of the quadratic equation

ax2 + bx + c = 0

and 3b2 = 16ac         ...(i)

 α + β = - ba and αβ = ca    ...(ii)

From Eq. (i), we get

                   3b . b = 16a . c

                   3ba2 = 16ca               divide by a2              3α + β2 = 16αβ          from Eq. (ii) 3α2 + 3β2 + 6αβ = 16αβ             3α2 + 3β2 = 10αβ       3αβ + 3βα = 10

Let                              αβ = xThen,                 3x + 3x = 10           3x2 - 10x + 3 = 0 3xx - 3 - 1x - 3 = 0          x - 33x - 1 = 0                                 x = 3, 13                               αβ = 13, 3                β = 3α or α = 3β


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73.

The number of solutions of the equation

12log3x + 1x +5 + logex + 52 = 1

  • 0

  • 1

  • 2

  • infinite


74.

If sinα, cosα  be the roots of the equation x2 - bx + c = 0, Then, which of the following statements is/are correct?

  • c 12

  • b  2

  • c > 12

  • > 2


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75.

If α + β and α - β are the roots of the equation x2 + px + q = 0, where α, β, p and q are real, then the roots of the equation (p2 - 4q)(p2x2 + 4px) - 16q = 0 are

  • 1α + 1β and 1α - 1β

  • 1α + 1β and 1α - 1β

  • 1α + 1β and 1α - 1β

  • α + β and α - β


76.

The number of solutions of the equation log2x2 + 2x - 1 = 1 is

  • 0

  • 1

  • 2

  • 3


77.

Let R be the set of real numbers and the functions f : R ➔ R and g : R ➔ R be defined by f(x) = x2 + 2x - 3 and g(x) = x + 1. Then, the value of x for which f(g(x)) = g(f(x)) is

  • - 1

  • 0

  • 1

  • 2


78.

The maximum value of z, when the complex number z satisfies the condition z + 2z = 2 is

  • 3

  • 3 + 2

  • 3 + 1

  • 3 - 1


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79.

If 32 + i3250 = 325x +iy, where x and y are real, then the ordered pair (x, y) is

  • - 3, 0

  • 0, 3

  • 0, - 3

  • 12, 32


80.

If z - 1z + 1 is pure imaginary, then

  • z = 12

  • z = 1

  • z = 2

  • z = 3


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