Find the values of 'a' for which the expression x2 - (3a - 1)x + 2a2 + 2a - 11 is always positive
The value of (1 - w + w2)5 + (1 + w - w2)5, where w and w2 are the complex cube roots of unity, is
0
32w
- 32
32
If one root of the equation x2 + (1 - 3i)x - 2(1 + i) = 0 is - 1 + i, then the other root is
- 1 - i
i
2i
The equation has
no real root
one real root
two real root
four real root
D.
four real root
Thus, the given equation has four real roots.
For two complex numbers z1, z2 the relation holds, if
arg(z1) = arg(z2)
arg(z1) + arg(z2) =
z1z2 = 1
The region of the complex plane for which = 1, [Re (a) 0] is
x - axis
y - axis
the straight line x = a
None of the above
Let be the roots of x2 + x + 1 = 0, then the equation whose roots are is
x2 - x + 1 = 0
x2 + x - 1 = 0
x2 + x + 1 = 0
x60 + x30 + 1 = 0