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 Multiple Choice QuestionsMultiple Choice Questions

161.

The minimum area of the triangle formed by any tangent to the ellipse ( x2/a2 ) + ( y2/b2 ) = 1 with the coordinate axes is

  • a2 + b2

  • ( a + b )2/2

  • ab

  • ( a - b )2/2


162.

If the line lx + my - n = 0 will be a normal to the hyperbola, then a2l2 - b2m2 = a2 + b22k, where k is equal to

  • n

  • n2

  • n3

  • None of these


163.

Equation of the chord of the hyperbola 25x2  - 16y2 = 400 which is bisected at the point (6, 2), is

  • 6x - 7y = 418

  • 75x - 16y = 418

  • 25x - 4y = 400

  • None of these


164.

The centres of a set of circles, each of radius 3, lie on the circles x2 + y2 = 25. the locus of any point in the set is

  • 4  x2 +_y2  64

  • x2 + y2  25

  • x2 + y2  25

  • 3  x2 + y2  9


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165.

The angle of intersection of the circles x2 + y2 - x + y - 8 = 0 and x2 + y2 + 2x + 2y - 11 = 0 is

  • tan-1199

  • tan-119

  • tan-1919

  • tan-19


C.

tan-1919

We know that, angle of intersection between two circles is given by

cosθ = r12 +r22 - d22r1r2 = 172 + 13 - 1042172 . 13                             here, r1 = 122 + - 122 + 8             = 172,r            2 = 13and d = c1c2 = 102 cosθ = 19442or   tanθ = 919        θ = tan-1919


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166.

If a tangent having slope of - 43 to the ellipse x218 + y232 = 1 intersects the major and minor axes in points A and B respectively, then the area of OAB is equal to (O is centre of the ellipse)

  • 12 sq units

  • 48 sq units

  • 64 sq units

  • 24 sq units


167.

The locus of mid-points of tangents intercepted between the axes of ellipse x2a2 + y2b2 = 1 will be

  • a2x2 + b2y2 = 1

  • a2x2 + b2y2 = 2

  • a2x2 + b2y2 = 3

  • a2x2 + b2y2 = 4


168.

If PQ is a double ordinate of hyperbola (x2/a2) - (y2/b2) = 1 such that OPQ is a equilateral triangle, O being the centre of the hyperbola, then the eccentricity 'e' of the hyperbola satisfies

  • 1 < e < 2/√3

  • e = 2/√3

  • e = √3/2

  • e > 2/√3


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169.

The lines 2x - 3y - 5 = 0 and 3x - 4y = 7 are diameters of a circle of area 154 sq units, then the equation of the circle is

  • x2 + y2 + 2x - 2y - 62 = 0

  • x2 + y2 + 2x - 2y - 47 = 0

  • x2 + y2 - 2x + 2y - 47 = 0

  • x2 + y2 - 2x + 2y - 62 = 0


170.

The angle of depressions of the top and the foot of a chimney as seen from the top of a second chimney, which is 150 m high and standing on the same level as the first are θ and ∅ respectively, then the distance between their tops when tan θ = 4/3 and tan ∅ = 5/2 is

  • 150/√3 m

  • 100√3 m

  • 150 m

  • 100 m


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