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 Multiple Choice QuestionsMultiple Choice Questions

231.

The equation of the tangent at the vertex of the parabola x2 + 4x + 2y = 0, is

  • x = - 2

  • x = 2

  • y = - 2

  • y = 2


232.

The distance between the directrices of the ellipse x24 + y29 = 1 is

  • 95

  • 185

  • 245

  • None of these


233.

The equation of the normal to the hyperbola x2 - 16y2 - 2x - 64y - 72 = 0 at the point (- 4, - 3) is

  • 5x + 16y + 79 = 0

  • 16x + 5y + 97 = 0

  • 16x + 5y + 79 = 0

  • 5x + 16y + 97 = 0


234.

The centre of the circle which circumscribes the square formed by x2 - 8x + 12 = 0 and y2 - 14y + 45 = 0 is

  • (4, 5)

  • (3, 4)

  • (9, 5)

  • (4, 7)


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235.

If e1 and e2 are the eccentricities of the hyperbolas x2a2 - y2b2 = 1 and x2a2 - y2b2 = - 1, then the value of 1e12 + 1e22 is

  • 3

  • 2

  • 1

  • 12


236.

The point of contact of 3x + 4y + 7 = 0 and x2 + y2 - 4x - 6y -12 = 0 is

  • (1, 1)

  • (- 1, 1)

  • (1, - 1)

  • ( -1, - 1)


237.

The equation x2 - 7xy + 12y2 = 0 represents a

  • circle

  • pair of parallel straight lines

  • pair of perpendicular straight lines

  • pair of non-perpendicular straight lines


238.

The locus of z given by z - 1z +1 = 1 is

  • a parabola

  • an ellipse

  • a circle

  • a straight line


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239.

A conic section represents a circle, if its eccentricity e is

  • e < 0

  • e > 0

  • e = 0

  • None of these


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240.

The equation of circle passing through the points (0, 2) (3, 3) and having its centre on the x-axis is

  • x2 + y2 - 14x - 12 = 0

  • 3x2 + 3y2 - 22x - 4 = 0

  • 3x2 + 3y2 - 14x - 12 = 0

  • None of the above


C.

3x2 + 3y2 - 14x - 12 = 0

Given, centre of the circle lies on x-axis.

 Centre of the circle = (- g, 0).

Then, equation of the circle is

x +g2 + y2 = g2 - c2 x2 + g2 +2xg + y2 = g2 - c  x2 + 2xg + y2 + c = 0      ...iThis circle passes through the point (0, 2). 0 + 20g + 22 + c = 0                                 c = - 4On putting the value of c in Eq. (i), we get        x2 + 2xg + y2 - 4 = 0     ...(ii)This circle also passes through the point (3, 3). 32 + 23g + 32 - 4 = 0 6g = - 14  g = - 146 = - 73On putting the value of g in Eq. (ii), we get    x2 + 2- 73x + y2 - 4 = 0 3x2 + 3y2 - 14x - 17 = 0which is required equation of circle.


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