A metal 'M' reacts with N2 to give a compound 'A' (M3N). 'A' on heating at high temperature gives back 'M' and 'A' on reacting with H2O give a gas B. 'B' turns CuSO4 solution blue on passing through it. M and B can be
Al and NH3
Li and NH3
Na and NH3
Mg and NH3
CH3CH2CH(OH)CH3 and CH3(CH2)2CH2OH can be distinguished by
Lucas test
Iodoform test
Victor-Meyer's test
All of the above
The compound which does not exhibit geometrical isomerism, is
CH3CH=CHCOOH
Br-CH=CH-Br
C6H5CH=NOH
D.
In case of acyclic compounds, presence of atleast one double bond between two carbon atoms or between carbon and nitrogen atoms is an essential condition for exhibiting geometrical isomerism. In case of cyclic compounds, different groups are present at the same carbon atoms and atleast one same group is present at successive carbon atoms.
Therefore, option d does not satisfy these compounds, thus it does not exhibit geometrical isomerism.
Which of the following is the most reactlve towards ring nitration ?
benzene
toulene
m-xylene
mesitylene
Racemic compound has
equimolar mixture of enantiomers
1 : 1 mixture of enantiomer and diastereomer
1 : 1 mixture of diastereomers
1 : 2 mixture of enantiomers
In which of the following ways does the hydride ion tend to function ?
An electrophile
A nucleophile
A free radical
An acid