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 Multiple Choice QuestionsMultiple Choice Questions

21.

Gaseous benzene reacts with hyodrogen gas in presence of a nickel catalyst to form gaseous cyclohexane according to the reaction, 

C6H6 (g) + 3H2 (g) → C6H12 (g)

A mixture of C6H6 and excess H2 has a pressure of 60 mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane, the pressure of the gas was 30 mm of Hg in the same volume at the same temperature. The fraction of C6H6 (by volume) present in the original volume is

  • 1/3

  • 1/4

  • 1/5

  • 1/6


22.

The dissolution of Al(OH)3 by a solution of NaOH results in the formation of

  • [Al(H2O)4(OH)2]+

  • [Al(H2O)3(OH)3]

  • [Al(H2O)2(OH)4]-

  • [Al(H2O)6(OH)3


23.

The molarity of NO3- in the solution after 2L of 3M AgNO3 is mixed with 3L of 1M BaCl2 is

  • 1.2 M

  • 1.8 M

  • 0.5 M

  • 0.4 M


24.

2.76 g of silver carbonate on being strongly heated yields a residue weighing

  • 3.45g 

  • 3.0g

  • 1.36g

  • 2.16g


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25.

Which has the maximum number of molecules among the following?

  • 44 g CO2

  • 48 g O3

  • 8g H2

  • 64g SO2


26.

1.5 g of CdCl2 was found to contain 0.9 g of Cd. Calculate the atomic weight of Cd.

  • 118

  • 112

  • 106.5

  • 53.25


27.

How many 'mL' of perhydrol is required to produce sufficient oxygen which can be used to completely convert 2 L of SO2 gas to SO3 gas?

  • 10 mL

  • 5 mL

  • 20 mL

  • 30 mL


28.

The cubic unit cell of a metal (molar mass = 63.55 g mol-1) has an edge length of 362 pm. Its density is 8. 92 g cm-3. The type of unit cell is

  • primitive

  • face centred

  • body centred

  • end centred


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29.

The number of hydrogen atoms present in 25.6 g of sucrose (C12H22O11) which has a molar mass of 342.3 g is

  • 22 × 1023

  • 9.91 × 1023

  • 11 × 1023

  • 44 × 1023 H atoms


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30.

The number of formula units of calcium fluoride, CaF2 present in 146.4 g of CaF(the molar mass of CaF2is 78.08 g/mol) is

  • 1.129 × 1024 CaF2

  • 1.146 × 1024 CaF2

  • 7.808 × 1024 CaF2

  • 1.877 × 1024 CaF2


A.

1.129 × 1024 CaF2

CaF2 = 146.4 gmolecular weight of CaF2= 78.08 g/molMoles of CaF2=wtmo.wt                           = 146.478.08=  1.875 molNumber of CaF2 atoms in 146.4 g ofCaF2= No of moles × 6.022×1023                                                  = 1.875 × 6.022 × 1023                                                  = 11.29 × 1023                                                    = 11.29 ×1024 CaF2                                                                                


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