Heat liberated with 100 mL of 1 N NaOH is neutralised by 300 mL of 1 N HCl
11.56 kJ
5.73 kJ
22.92 kJ
17.19 kJ
B.
5.73 kJ
The molarity and normality are same in case of NaOH and HCl because the acidity and basicity of these are one and one respectively,
Since, number of moles = molarity × volume (l)
Number of moles of NaOH solution =
And number of moles of HCl solution = = 0.3
Hence, 0.1 mole NaOH is neutralised by 0.1 mole HCl. We know that heat of neutralisation of 1 mole HCl and 1 mole NaOH is 57.3 kJ. Hence, heat of neutralisation of 0.1 mole HCl and 0.1 mole
NaOH will be = 57.3 × 0.1 = 5.73 kJ
A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is
6N
2N
4N
8N
4g of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave 5 g of its oxide. The equivalent weight of copper is
23
32
12
20
The equivalent weight of a certain trivalent element is 20. Molecular weight of its oxide is
152
56
168
68
An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be
A3B6
A2B3
A3B2
A2B
What is the equivalent weight of SnCl2 in the following reaction?
SnCl2 + Cl2 → SnCl4
95
45
60
30