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 Multiple Choice QuestionsMultiple Choice Questions

181.

The maximum value of fx = logxxx  0, x  1 is

  • e

  • 1e

  • e2

  • 1e2


182.

If the volume of spherical ball is increasing at the rate of 4π cm3/s, then the rate of change of its surface area when the volume is 288 π cm3, is

  • 43π cm2/s

  • 23π cm2/s

  • 4π cm2/s

  • 2π cm2/s


183.

The equation of displacement of a particle is x(t) = 5t2 - 7t + 3. The acceleration at the moment when its velocity becomes 5 m/sec is

  • 3 m/sec2

  • 7 m/sec2

  • 10 m/sec2

  • 8 m/sec2


184.

The mean value of the function fx = 2ex + 1 on the interval [0, 2] is

  • 2 - loge2e2 + 1

  • 2 + loge2e2 + 1

  • 2 + loge2e2 - 1

  • - 2 + loge2e2 - 1


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185.

The function y = 2x - x2

  • increases in (0, 1) but decreases in (1, 2)

  • decreases in (0, 2)

  • increases m (1, 2) but decreases in (0, 1)

  • increases in (0, 2)


186.

The interval in which the function y = x - 2sinx0  x  2π increases throughout is

  • 5π3, 2π

  • 0, π3

  • π3, 5π3

  • 0, π4


187.

The points of the curve y = x3 + x - 2 at which its tangent are parallel to the straight line y = 4x - 1 are

  • (2, 7), (- 2, - 11)

  • (0, 2), (21/3, 21/3)

  • (- 21/3, - 21/3), (0, - 4)

  • (1, 0), (- 1, - 4)


188.

The equation of the normal to the curve y = - x + 2 at the point of its intersection with the bisector of the first quadrant is

  • 4x - y + 16 = 0

  • 4x - y = 16

  • 2x - y - 1 = 0

  • 2x - y + 1 = 0


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189.

The angle at which the curve y = x2 and the curve x = 53cost, y = 54sint intersect is

  • tan-1241

  • tan-1412

  • - tan-1241

  • 2tan-1412


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190.

The maximum value of the function y = 2tanx - tan2x over 0, π2 is

  • 1

  • 3

  • 2


B.

1

Given, y = 2tanx - tan2x        ...i    dydx = 2sec2x - 2tanxsec2x              = 2sec2x1 - tanx    ...iiAt point of maxima,        dydx = 02sec2x1 - tanx = 0     From Eq. (ii)       x = π4, π2     Here, x = π2 is not possible       x = π4      as given x  0, π2Now, d2ydx2 = 4sec2xtanx1 - tanx + 2sec2x0 - sec2x                = 4sec2xtanx - 4sec2xtan2x - 2sec4x d2ydx2x = π4               = 4sec2π4tanπ4 - 4sec2π4tan2π4 - 2sec4π4               = 422 . 1 - 422 . 12 - 2 . 24               = 8 - 8 - 8               = - 8, which is negative At x = π4, function y = 2tanx - tan2x has maximum value. Maximum value of function at point x = π4 will beyx = π4 = 1


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