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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

71.

$bold N subscript bold 2 bold O subscript bold 5 bold space bold rightwards arrow bold space bold 2 bold NO subscript bold 2 bold space bold plus bold space bold 1 over bold 2 bold O subscript bold 2 bold space$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ $bold t subscript begin inline style bold 1 over bold 2 end style end subscript bold space bold equals bold space bold 24$ àª•àª²àª¾àª• àª›à«‡. 10 àª—à«àª°àª¾àª® N₂O₅ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€ 96 àª•àª²àª¾àª• àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ N₂O₅ àª¨à«‹ àªœàª¥à«àª¥à«‹ àª•à«‡àªŸàª²à«‹ àª¹àª¶à«‡ ?

1.25 àª—à«àª°àª¾àª®
1.77 àª—à«àª°àª¾àª®
0.63 àª—à«àª°àª¾àª®
0.5 àª—à«àª°àª¾àª®

72. પ્રથમ ક્રમની એક પ્રક્રિયામાં 75 % પ્રક્રિયકનું વિઘટન 1.386 કલાકમાં થાય છે. આ પ્રક્રિયાનો વેગ-અચળાંક જણાવો.

$1.8 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$2.8 space cross times space 10 to the power of negative 4 end exponent space straight s to the power of negative 1 end exponent$
$17.2 space cross times 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$3.6 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$

73.

46.06 àª®àª¿àª¨àª¿àªŸ
460.6 àª®àª¿àª¨àª¿àªŸ
23.03 àª®àª¿àª¨àª¿àªŸ
230.5 àª®àª¿àª¨àª¿àªŸ

74.

20 àª®àª¿àª¨àª¿àªŸ
40 àª®àª¿àª¨àª¿àªŸ
10 àª®àª¿àª¨àª¿àªŸ
80 àª®àª¿àª¨àª¿àªŸ

40 àª®àª¿àª¨àª¿àªŸ

$1 space rightwards arrow for straight t subscript bevelled 1 half end subscript of 1 half rightwards arrow for straight t subscript begin inline style bevelled 1 half end style end subscript of$ àª®àª¾àªŸà«‡ $straight T space equals space straight n space times space straight t subscript begin inline style 1 half end style end subscript$

$therefore space straight t subscript begin inline style bevelled 1 half end style end subscript space equals space straight T over straight n space equals space 20 over 2 space equals space 10 space$ àª®àª¿àª¨àª¿àªŸ

$1 space rightwards arrow for straight t subscript begin inline style bevelled 1 half end style end subscript of space 1 half space rightwards arrow for straight t subscript begin inline style bevelled 1 half end style end subscript of fraction numerator 1 space over denominator 4 end fraction rightwards arrow for straight t subscript begin inline style bevelled 1 half end style end subscript of 1 over 8 rightwards arrow for straight t subscript begin inline style bevelled 1 half end style end subscript of 1 over 16$

$therefore space straight T space equals space 4 space cross times space 10 space equals space 40 space$ àª®àª¿àª¨àª¿àªŸ

75.

15 àª®àª¿àª¨àª¿àªŸ
45 àª®àª¿àª¨àª¿àªŸ
60 àª®àª¿àª¨àª¿àªŸ
30 àª®àª¿àª¨àª¿àªŸ

76.

360 àª®àª¿àª¨àª¿àªŸ
300 àª®àª¿àª¨àª¿àªŸ
398.8 àª®àª¿àª¨àª¿àªŸ
400 àª®àª¿àª¨àª¿àªŸ

77.

$3.466 space cross times 10 to the power of negative 3 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 4 end exponent straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 5 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

78.

$fraction numerator 0.346 over denominator straight K end fraction$
$fraction numerator 0.25 over denominator straight K end fraction$
$fraction numerator 0.29 over denominator straight K end fraction$
$fraction numerator 1.38 over denominator straight K end fraction$

79. પ્રક્રિયાની પૂર્ણતા પ્રાપ્ત કરવા માટે પ્રક્રિયકના અણુઓ પાસે જરૂરી ઓછામાં ઓછી ઊર્જા એટલે .....

સ્થિતિમાન ઊર્જા
દેહલી ઊર્જા
આંતરિક ઊર્જા
સક્રિયકરણ ઊર્જા

80. નીચેના પૈકી કયું સાચું આર્હેનિયસ સમીકરણ છે ?

$straight K space equals space straight A space times space straight e to the power of begin inline style bevelled fraction numerator negative Ea over denominator RT end fraction end style end exponent$
$In space straight K space equals space In space straight A space minus space Ea over RT$
$In space straight K subscript 2 over straight K subscript 1 space equals space Ea over straight R space open parentheses 1 over straight T subscript 1 space minus space 1 over straight T subscript 2 close parentheses$
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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

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