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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

91.

àª¬à«‡ àªœà«àª¦à«€-àªœà«àª¦à«€ àª°àª¾àª¸àª¾àª¯àª£àª¿àª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª“àª¨àª¾ àªµà«‡àª—-àª…àªšàª³àª¾àª‚àª• àª…àª¨à«àª•à«àª°àª®à«‡ K₁ = 10¹⁶ $bold times bold space bold e to the power of begin inline style bevelled fraction numerator bold minus bold 2000 over denominator bold T end fraction end style end exponent$ àª…àª¨à«‡ $bold K subscript bold 2 bold space bold equals bold space bold 10 to the power of bold 15 bold space bold times bold space bold e to the power of begin inline style bevelled fraction numerator bold minus bold 1000 over denominator bold T end fraction end style end exponent$ àª›à«‡. àª•àª¯àª¾ àª•à«…àª²à«àªµàª¿àª¨ àª¤àª¾àªªàª®àª¾àª¨à«‡ K₁ = K₂ àª¥àª¾àª¯ ?

2000 K
1000 K
$fraction numerator 2000 over denominator 2.303 end fraction space straight K$
$fraction numerator 1000 over denominator 2.303 end fraction space straight K$

92.

10 àª•àª¿.àª•à«…àª²àª°à«€ àª®à«‹àª²^-1
20àª•àª¿.àª•à«…àª²àª°à«€ àª®à«‹àª²^-1
15 àª•àª¿.àª•à«…àª²àª°à«€ àª®à«‹àª²^-1
àª¶à«àª¨à«àª¯

93.

$bold C subscript bold 2 bold H subscript bold 5 bold I bold space bold plus bold space bold OH to the power of bold minus bold space bold rightwards arrow bold space bold C subscript bold 2 bold H subscript bold 5 bold OH bold space bold plus bold space bold I to the power of bold minus$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª®àª¾àªŸà«‡ 30 $degree$ àª…àª¨à«‡ 60 $degree$ àª¸à«‡. àª¤àª¾àªªàª®àª¾àª¨à«‡ àªµà«‡àª—-àª…àªšàª³àª¾àª‚àª• àª…àª¨à«àª•à«àª°àª®à«‡ 0.325 àª…àª¨à«‡ 6.735 àª²àª¿àªŸàª° àª®à«‹àª²^-1 àª¸à«‡àª•àª¨à«àª¡^-1 àª¹à«‹àª¯ àª¤à«‹ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«€ àª¸àª•à«àª°àª¿àª¯àª•àª°àª£ àªŠàª°à«àªœàª¾àª¨à«àª‚ àª®à«‚àª²à«àª¯ àª•à«‡àªŸàª²à«àª‚ àª¹àª¶à«‡ ?

84773 àª•à«…àª²àª°à«€
20260 àª•àª¿. àª•à«…àª²àª°à«€
361.44 àª•àª¿. àª•à«…àª²àª°à«€
20260 àª•à«…àª²àª°à«€

94.

64 àª—àª£à«‹
10 àª—àª£à«‹
32 àª—àª£à«‹
24 àª—àª£à«‹

95.

0.1
0.002
0.01
0.001

96. એક ઉષ્માક્ષેપક પ્રક્રિયાની પુરોગામી પ્રક્રિયા અને પ્રતિગામી પ્રક્રિયાની સક્રિયકરણ ઊર્જા અનુક્રમે E_f અને E_r હોય, તો

E_f = E_r
E_f < E_r
$straight E subscript straight f space greater than space straight E subscript straight f$
$straight E subscript straight f space greater than greater than greater than space straight E subscript straight r$

97.

$fraction numerator straight K subscript 1 apostrophe over denominator straight K subscript 1 end fraction space space equals space fraction numerator straight K subscript 2 apostrophe over denominator straight K subscript 2 end fraction space equals space 0$
$fraction numerator straight K subscript 1 apostrophe over denominator straight K subscript 1 end fraction space equals space fraction numerator straight K subscript 2 apostrophe over denominator straight K subscript 2 end fraction$
$fraction numerator straight K subscript 1 apostrophe over denominator straight K subscript 1 end fraction space greater than space fraction numerator straight K subscript 2 apostrophe over denominator straight K subscript 2 end fraction$
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

98.

I. $bold A bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold space bold space bold K subscript bold 1 bold space bold space bold space bold space bold space bold space bold space bold space on top bold space bold B$ àª¸àª•à«àª°àª¿àª¯àª•àª°àª£ àªŠàª°à«àªœàª¾ E₁
II. $bold A bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold space bold space bold K subscript bold 2 bold space bold space bold space bold space bold space bold space bold space bold space on top bold space bold C$ àª¸àª•à«àª°àª¿àª¯àª•àª°àª£ àªŠàª°à«àªœàª¾ E₂ àª›à«‡, àªªàª°àª‚àª¤à« E₂ = 2E₁ àªœà«‹ àª¹à«‹àª¯, àª¤à«‹ K₁ àª…àª¨à«‡ K₂ àªµàªšà«àªšà«‡ àª•àª¯à«‹ àª¸àª‚àª¬àª‚àª§ àª›à«‡ ?

$straight K subscript 1 space equals space 2 straight K subscript 2 space times space straight e to the power of begin inline style bevelled straight E subscript 2 over RT end style end exponent$
$straight K subscript 1 space equals space straight K subscript 2 space times space straight A space times space straight e to the power of begin inline style bevelled straight E subscript 1 over RT end style end exponent$
$straight K subscript 2 space equals space straight K subscript 1 space times space straight e to the power of begin inline style bevelled straight E subscript 2 over straight T end style end exponent$
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

99.

1.289 àª—àª£à«‹
12.89 àª—àª£à«‹
0.129 àª—àª£à«‹
25 %

1.289 àª—àª£à«‹

$therefore space log space equals space straight K subscript 2 over straight K subscript 1 space equals space fraction numerator Ea space times space increment straight T over denominator 2.303 space straight R space space space straight T subscript 1 space times space straight T subscript 2 end fraction space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 9000 space cross times space 5 over denominator 2.303 space cross times space 2 space cross times space 295 space cross times space 300 end fraction space space space space space space space space space space space space space space space space space space space space space equals space 0.1104 log space straight K subscript 2 over straight K subscript 1 space equals space 0.1104 therefore space straight K subscript 2 over straight K subscript 1 space equals space 1.289 therefore space straight K subscript 2 space equals space straight K subscript 1 space cross times space 1.289$

100.

ΛH àª¬àª°àª¾àª¬àª°
àª¶à«‚àª¨à«àª¯
ΛH àª¥à«€ àª“àª›à«àª‚
ΛH àª¥à«€ àªµàª§à«

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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

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