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Gujarati JEE Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

Multiple Choice Questions

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41.
bold Ni bold space bold vertical line bold space bold Ni to the power of bold 2 subscript bold left parenthesis bold 0 bold. bold 001 bold M bold right parenthesis end subscript bold space bold vertical line bold vertical line bold Ag to the power of bold 2 bold right parenthesis bold 0 bold. bold 01 bold M bold right parenthesis bold space bold vertical line bold space bold Ag કોષના તાપમાનમાં વધારો કરતાં કોષ- પોટૅન્શિયલમાં સૈદ્વાંતિક રીતે કયો ફેરાફર થશે ?

  • ઘટશે. 

  • વધશે.

  • ફેરફાર ના થાય. 

  • કહી ના શકાય.

A.

ઘટશે. 

Ni space vertical line space space Ni subscript left parenthesis 0.001 straight M right parenthesis end subscript superscript 2 plus end superscript space vertical line space Ag subscript left parenthesis 0.01 straight M right parenthesis end subscript superscript plus space vertical line space Ag કોષ માટે તાપમાનમા વધારો કરતાં

 

straight T space less than space straight T subscript 1 space space space therefore space fraction numerator RT over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction space less than space fraction numerator RT subscript 1 over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator left square bracket Ag to the power of plus right square bracket squared end fraction left parenthesis because space straight Q space greater than space 1 right parenthesis space space space therefore space fraction numerator RF over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction space greater than space space minus space fraction numerator RT subscript 1 over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction

Ni space vertical line space space Ni subscript left parenthesis 0.001 straight M right parenthesis end subscript superscript 2 plus end superscript space vertical line space Ag subscript left parenthesis 0.01 straight M right parenthesis end subscript superscript plus space vertical line space Ag કોષ માટે તાપમાનમા વધારો કરતાં

 

straight T space less than space straight T subscript 1 space space space therefore space fraction numerator RT over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction space less than space fraction numerator RT subscript 1 over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator left square bracket Ag to the power of plus right square bracket squared end fraction left parenthesis because space straight Q space greater than space 1 right parenthesis space space space therefore space fraction numerator RF over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction space greater than space space minus space fraction numerator RT subscript 1 over denominator 2 straight F end fraction space log space fraction numerator open square brackets Ni to the power of 2 plus end exponent close square brackets over denominator open square brackets Ag to the power of plus close square brackets squared end fraction

Answer
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    42.
    bold Co bold space bold vertical line bold space bold Co to the power of bold 2 subscript bold left parenthesis bold C subscript bold 1 bold right parenthesis end subscript bold thin space bold vertical line bold vertical line bold space bold Sn to the power of bold 2 subscript bold left parenthesis bold C subscript bold 2 bold right parenthesis end subscript bold space bold vertical line bold space bold Sn કોષ માટે C2 > C1 હોય, તો બંબે અર્ધ-કોષનાં દ્વાવણોની સાંદ્વતામાં સમાન 0.1 M નો વધારો કરતાં કોષ-પોટૅન્શિયલમાં શું ફેરફાર થાય ?

    • વધશે.

    • કોઈ ફેરફાર ના થાય. 

    • ઘટશે. 

    • કહી ના શકાય.

    Answer
    • 43.
    bold Zn bold space bold vertical line bold space bold Zn to the power of bold 2 subscript bold left parenthesis bold 0 bold. bold 04 bold M bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold space bold Ag subscript bold left parenthesis bold C subscript bold 2 bold right parenthesis end subscript bold space bold vertical line bold space bold Agવિદ્યુત રાસાયણિક કોષ માટે bold E subscript bold cell bold space bold equals bold space bold E to the power of bold 0 subscript bold cell હોય, તો C2 નું મૂલ્ય આપેલમાંથી કયું હોઈ શકે છે ?

    • 0.2M

    • 0.0016M

    • 0.02M

    • 0.04M

    Answer
    • 44. bold Pt bold space bold vertical line bold space bold H subscript bold 2 bold left parenthesis bold g bold. bold 1 bold. bold બ ા ર bold space bold right parenthesis end subscript bold thin space bold vertical line bold space bold OH to the power of bold minus subscript bold left parenthesis bold aq bold right parenthesis end subscript bold spaceઅર્ધકોષમાં થતી ઑક્સિડેશન પ્રક્રિયા જણાવો.
    • 2 straight H subscript 2 straight O space plus space 2 OH to the power of minus subscript left parenthesis aq right parenthesis end subscript space rightwards harpoon over leftwards harpoon space 3 straight H subscript 2 straight O subscript 1 space plus space 2 straight e to the power of minus
    • straight H subscript 2 left parenthesis straight g right parenthesis end subscript space plus space 2 OH to the power of minus subscript left parenthesis aq right parenthesis end subscript space rightwards harpoon over leftwards harpoon space 2 straight H subscript 2 straight O subscript left parenthesis 1 right parenthesis end subscript space plus space 2 straight e to the power of minus
    • straight H subscript 2 left parenthesis straight g right parenthesis end subscript space plus space 2 OH to the power of minus subscript left parenthesis aq right parenthesis end subscript space rightwards harpoon over leftwards harpoon space 2 straight H subscript 2 straight O subscript 1 space plus space straight O subscript 2 left parenthesis straight g right parenthesis end subscript space plus space 2 straight e to the power of minus

    • આપેલ પૈકી એક પણ નહી.

    Answer
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    45.

    bold Mg bold space bold vertical line bold space bold Mg to the power of bold 2 subscript bold left parenthesis bold C subscript bold 1 bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold Fe to the power of bold 2 subscript bold left parenthesis bold 0 bold. bold 5 bold M bold right parenthesis end subscript bold space bold vertical line bold space bold Fe કોષમા નિયત તાપમાને બંને દ્વાવણોની સાંદ્વતામાં સમાન 0.1 M નો ઘટાડો કરતાં કોષ-પોટૅન્શિયલ વધે છે, તો C1 નું મૂલ્ય આપેલ મૂલ્યોમાંથી કયું મૂલ્ય હોઈ શકે ?

    • 0.4 M

    • 0.5M

    • 0.7M

    • આપેલ પૈકી એક પણ નહી.

    Answer
    • 46.
    bold Ni bold space bold vertical line bold space bold Ni to the power of bold 2 subscript bold left parenthesis bold C subscript bold 1 bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold Cu to the power of bold 2 subscript bold left parenthesis bold 0 bold. bold 4 bold M bold right parenthesis end subscript bold space bold vertical line bold space bold Cu કોષમાં નિયત તાપમાને બંને દ્વાવણોની સાંદ્વતામાં સમાન 0.1 નો વધારો કરતાં કોષ-પોટૅન્શિયલ વધે છે, તો C1 નું મૂલ્ય આપેલ મૂલ્યોમાંથી કયું મૂલ્ય હોઈ શકે ?

    • 0.4 M

    • 0.1 M

    • 0.8 M

    • કહી ના શકાય.

    Answer
    • 47. bold Cd bold space bold vertical line bold space bold Cd to the power of bold 2 subscript bold left parenthesis bold C subscript bold 1 bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold Cu to the power of bold 2 subscript bold left parenthesis bold C subscript bold 2 bold right parenthesis end subscript bold space bold vertical line bold space bold Cu કોષ માટે Ecell > E0cell હોય, તો બંને અર્ધ-કોષનાં દ્વાવણોની સાંદ્વતામાં સમાન 0.1 M નો ઘટાડો કરતાં કોષ-પોટૅન્શિયલમાં શું ફેરફાર થાય ? (C1અને C2 > 0.1 M)

    • ઘટશે.

    • કોઈ ફેરફાર ના થાય. 

    • કહી ના શકાય.

    • વધશે. 

    Answer
    • 48.
    bold Fe bold space bold vertical line bold space bold Fe to the power of bold 2 subscript bold left parenthesis bold C subscript bold 1 bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold Cl to the power of bold minus subscript bold left parenthesis bold C subscript bold 2 bold right parenthesis end subscript bold space bold vertical line bold space bold Ptકોષ માટે નિયત તાપમાને કૅથોડના દ્વાવણની સાંદ્વતામાં વધારો કરતા કોષ પોટૅન્શિયલમાં શું ફરેફાર થયો ?

    • વધશે.

    • ઘટશે. 

    • કોઈ ફેરફાર ના થાય.

    • Ecell = Ecell થાય.

    Answer
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    49.
    25degreeસે તાપમાને Ag | Ag(0.4M) અને Al | Al3(0.1M) અર્ધકોષોને જોડતા રચાતા કોષનો પોટૅન્શિયલ 2.456 V હોય, તો કોષનો પ્રમાણિત પોટૅન્શિયલ કેટલો હશે ?

    • 2.46 V

    • 2.64 V

    • 1.46 V

    • 2.76 V

    Answer
    • 50.

    25degree સે તાપમાને કોષમાં થતી વાસ્તવિક પ્રક્રિયાને આધારે કયું કોષ-નિરૂપણ યોગ્ય નથી ?
    bold left parenthesis bold E to the power of bold 0 subscript bold Pb to the power of bold 2 bold plus end exponent bold space bold vertical line bold space bold Pb bold space end subscript bold equals bold space bold minus bold 0 bold. bold 13 bold V bold comma bold space bold E to the power of bold 0 subscript bold Sn to the power of bold 2 bold plus end exponent bold space bold vertical line bold space bold Sn end subscript bold space bold equals bold space bold minus bold 0 bold. bold 14 bold V bold right parenthesis

    • Pb | Pb2(0.01M) || Sn2(0.1M) | Sn

    • Sn | Sn2(0.05M) || Pb2 (0.5M) |Pb

    • Sn | Sn2(0.01M) || Pb2(0.01) | Pb

    • આપેલ પૈકી એક પણ નહી.

    Answer
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