15 àª®àª¿àª¨àª¿àªŸ àª…àª°à«àª§àª…àª¯à«àª·à«àª¯ àª¸àª®àª¯ àª§àª°àª¾àªµàª¤à«€ àªªà«àª°àª¥àª® àª•à«àª°àª®àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àªàª• àª•àª²àª¾àª• àªªàª›à«€ àªªà«àª°àª•à«àª°àª¿àª¯àª•àª¨à«‹ àª•à«‡àªŸàª²à«‹ àªœàª¥à«àª¥à«‹ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¶à«‡ ? from Chemistry રસાયણિક ગતિકી

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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

61.

àªªà«àª°àª¥àª® àª•à«àª°àª®àª¨à«àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àªªà«àª°àª•à«àª°àª¿àª¯àª•àª¨à«€ àª®à«àª³ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾ àª˜àªŸà«€àª¨à«‡ 25 % àª¥àª¤àª¾àª‚ àªàª• àª•àª²àª¾àª• àª²àª¾àª—à«‡ àª›à«‡. àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ àª…àª°à«àª§ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¸àª®àª¯ àªœàª£àª¾àªµà«‹.

30 àª®àª¿àª¨àª¿àªŸ
120 àª®àª¿àª¨àª¿àªŸ
4 àª•àª²àª¾àª•
15 àª®àª¿àª¨àª¿àªŸ

62. શુન્ય ક્રમની પ્રક્રિયા માટે .....

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63.

15 àª®àª¿àª¨àª¿àªŸ àª…àª°à«àª§àª…àª¯à«àª·à«àª¯ àª¸àª®àª¯ àª§àª°àª¾àªµàª¤à«€ àªªà«àª°àª¥àª® àª•à«àª°àª®àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àªàª• àª•àª²àª¾àª• àªªàª›à«€ àªªà«àª°àª•à«àª°àª¿àª¯àª•àª¨à«‹ àª•à«‡àªŸàª²à«‹ àªœàª¥à«àª¥à«‹ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¶à«‡ ?

$1 over 16$
$1 over 8$
$1 fourth$
$1 half$

B.

$1 over 8$

n àª…àª°à«àª§àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¸àª®àª¯à«‹ àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ àªœàª¥à«àª¥à«‹ $equals space bevelled straight alpha over 2 to the power of straight n$

$therefore space straight T space equals space straight n space times space straight t subscript begin inline style bevelled 1 half end style end subscript therefore space straight n space equals space straight T over straight t subscript bevelled 1 half end subscript space equals space 60 over 15 space equals space 4 space$
$therefore$ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ àªœàª¥à«àª¥à«‹ $equals space 1 over 2 to the power of 4 space equals space 1 over 16$

n àª…àª°à«àª§àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¸àª®àª¯à«‹ àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ àªœàª¥à«àª¥à«‹ $equals space bevelled straight alpha over 2 to the power of straight n$

$therefore space straight T space equals space straight n space times space straight t subscript begin inline style bevelled 1 half end style end subscript therefore space straight n space equals space straight T over straight t subscript bevelled 1 half end subscript space equals space 60 over 15 space equals space 4 space$
$therefore$ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ àªœàª¥à«àª¥à«‹ $equals space 1 over 2 to the power of 4 space equals space 1 over 16$

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64. નીચેના પૈકી કયું પ્રથમ ક્રમની પ્રક્રિયાનો પ્રક્રિયા સમય સૂચવે છે ?

$fraction numerator 2.303 over denominator straight K end fraction log space 4$
$fraction numerator 2.303 over denominator straight K end fraction log space 3$
$fraction numerator 2.303 over denominator straight K end fraction log 3 over 4$
$fraction numerator straight K over denominator 2.303 end fraction log space 4 over 3$

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65. પ્રથમ ક્રમની પ્રક્રિયા માટે

$straight t space equals space fraction numerator 2.303 over denominator straight K end fraction log fraction numerator straight a over denominator straight a plus space straight x end fraction$
$straight K space equals space fraction numerator 2.303 over denominator straight t end fraction log fraction numerator left square bracket straight A right square bracket over denominator left square bracket straight A right square bracket subscript 0 end fraction$
$left square bracket straight A right square bracket space equals space left square bracket straight A right square bracket subscript 0 times space straight e to the power of negative straight K times straight t end exponent$
$straight t space equals space straight K space cross times space 2.303 space log space fraction numerator left square bracket straight A right square bracket over denominator left square bracket straight A right square bracket subscript 0 end fraction$

66.

àªªà«àª°àª¥àª® àª•à«àª°àª®àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àª®à«‚àª³ àª¸àª¾àª¦à«àªµàª¤àª¾ $straight M over 10$ àª¥à«€ àª˜àªŸà«€àª¨à«‡ $bold M over bold 100$ àª¥àª¤àª¾àª‚ àª²àª—àªàª— àª•à«‡àªŸàª²à«‹ àª¸àª®àª¯ àª²àª¾àª—àª¶à«‡ ? àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ àª…àª°à«àª§ àª†àª¯à«àª·à«àª¯ àª¸àª®àª¯ 150 àª¸à«‡àª•àª¨à«àª¡ àª›à«‡.

600 àª¸à«‡àª•àª¨à«àª¡
500 àª¸à«‡àª•àª¨à«àª¡
900 àª¸à«‡àª•àª¨à«àª¡
1500 àª¸à«‡àª•àª¨à«àª¡

67.

àª¶à«àª¨à«àª¯ àª•à«àª°àª®àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ àª…àª°à«àª§àª†àª¯à«àª·à«àª¯ àª¸àª®àª¯ 1 àª•àª²àª¾àª• àª›à«‡. àªªà«àª°àª•à«àª°àª¿àª¯àª• A àª¨à«€ àª¶àª°à«‚àª†àª¤àª¨à«€ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾ 2 M àª›à«‡, àª¤à«‹ àª† àªœ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àªªà«àª°àª•à«àª°àª¿àª¯àª•àª¨à«€ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾ 0.5 M àª¥à«€ 0.25 Màª¥àªµàª¾ àª®àª¾àªŸà«‡ àª•à«‡àªŸàª²à«‹ àª¸àª®àª¯ àª²àª¾àª—àª¶à«‡ ?

0.25 àª•àª²àª¾àª•
1 àª•àª²àª¾àª•
4 àª•àª²àª¾àª•
0.5 àª•àª²àª¾àª•

68. જો પ્રક્રિયકની સાંદ્વતા x ગણી કરવામાં આવે, તો પ્રક્રિયાનો વેગ-અચળાંક = ............

$straight K times straight x$
K
$straight K over straight x$
$In straight K over straight x$

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69. n ક્રમની પ્રક્રિયાના પ્રક્રિયકની પ્રારભિક સાંદ્વતા a છે. પ્રક્રિયાનો અર્ધ આયુષ્ય સમય કોના સમપ્રમાણમાં હશે ?

aⁿ
a^n-1
a^1-n
aⁿ 1

70.

àªªà«àª°àª¥àª® àª•à«àª°àª®àª¨à«€ àªàª• àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ àª…àª°à«àª§àª†àª¯à«àª·à«àª¯ àª¸àª®àª¯ 14 àª•à«‡àª•àª¡ àª›à«‡. àª¤à«‡àª¨àª¾ àªªà«àª°àª•à«àª°àª¿àª¯àª•àª¨à«€ àª®à«‚àª³ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾àª¨à«‡ $bold 1 over bold 8$ àªœà«‡àªŸàª²à«€ àª¥àª¤àª¾àª‚ àª•à«‡àªŸàª²à«‹ àª¸àª®àª¯ àª²àª¾àª—àª¶à«‡ ?

28 àª¸à«‡àª•àª¨à«àª¡
42 àª¸à«‡àª•àª¨à«àª¡
(14)² àª¸à«‡àª•àª¨à«àª¡
(14)³ àª¸à«‡àª•àª¨à«àª¡

6
7
8

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