Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

71. પ્રથમ ક્રમની એક પ્રક્રિયામાં 75 % પ્રક્રિયકનું વિઘટન 1.386 કલાકમાં થાય છે. આ પ્રક્રિયાનો વેગ-અચળાંક જણાવો.

$1.8 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$2.8 space cross times space 10 to the power of negative 4 end exponent space straight s to the power of negative 1 end exponent$
$17.2 space cross times 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$3.6 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$

72.

46.06 àª®àª¿àª¨àª¿àªŸ
460.6 àª®àª¿àª¨àª¿àªŸ
23.03 àª®àª¿àª¨àª¿àªŸ
230.5 àª®àª¿àª¨àª¿àªŸ

73. નીચેના પૈકી કયું સાચું આર્હેનિયસ સમીકરણ છે ?

$straight K space equals space straight A space times space straight e to the power of begin inline style bevelled fraction numerator negative Ea over denominator RT end fraction end style end exponent$
$In space straight K space equals space In space straight A space minus space Ea over RT$
$In space straight K subscript 2 over straight K subscript 1 space equals space Ea over straight R space open parentheses 1 over straight T subscript 1 space minus space 1 over straight T subscript 2 close parentheses$
આપેલ બધા જ

74. પ્રક્રિયાની પૂર્ણતા પ્રાપ્ત કરવા માટે પ્રક્રિયકના અણુઓ પાસે જરૂરી ઓછામાં ઓછી ઊર્જા એટલે .....

સ્થિતિમાન ઊર્જા
દેહલી ઊર્જા
આંતરિક ઊર્જા
સક્રિયકરણ ઊર્જા

75.

$bold N subscript bold 2 bold O subscript bold 5 bold space bold rightwards arrow bold space bold 2 bold NO subscript bold 2 bold space bold plus bold space bold 1 over bold 2 bold O subscript bold 2 bold space$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ $bold t subscript begin inline style bold 1 over bold 2 end style end subscript bold space bold equals bold space bold 24$ àª•àª²àª¾àª• àª›à«‡. 10 àª—à«àª°àª¾àª® N₂O₅ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€ 96 àª•àª²àª¾àª• àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ N₂O₅ àª¨à«‹ àªœàª¥à«àª¥à«‹ àª•à«‡àªŸàª²à«‹ àª¹àª¶à«‡ ?

1.25 àª—à«àª°àª¾àª®
1.77 àª—à«àª°àª¾àª®
0.63 àª—à«àª°àª¾àª®
0.5 àª—à«àª°àª¾àª®

76.

$3.466 space cross times 10 to the power of negative 3 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 4 end exponent straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 5 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

$3.466 space cross times space 10 to the power of negative 4 end exponent straight M$ àª®àª¿àª¨àª¿àªŸ^-1

$straight K space equals space fraction numerator 2.303 over denominator straight t end fraction space log space open square brackets straight R close square brackets subscript 0 over open square brackets straight R close square brackets subscript straight t space equals space fraction numerator 2.303 over denominator 40 end fraction space log space fraction numerator 0.1 over denominator 0.025 end fraction space equals space fraction numerator 2.303 over denominator 40 end fraction space log space 4 space equals space 0.03466 space àª® àª¿ àª¨ àª¿ àªŸ à«‡ to the power of negative 1 end exponent$

àªªà«àª°àª•à«àª°àª¿àª¯àª¾àªµà«‡àª— $straight K space left square bracket straight R right square bracket space equals space 0.03466 space cross times space 0.01$

$equals space 3.466 space cross times space 10 to the power of negative 4 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸà«‡^-1

àªªà«àª°àª•à«àª°àª¿àª¯àª¾àªµà«‡àª— $straight K space left square bracket straight R right square bracket space equals space 0.03466 space cross times space 0.01$

$equals space 3.466 space cross times space 10 to the power of negative 4 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸà«‡^-1