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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

71. પ્રક્રિયાની પૂર્ણતા પ્રાપ્ત કરવા માટે પ્રક્રિયકના અણુઓ પાસે જરૂરી ઓછામાં ઓછી ઊર્જા એટલે .....

સ્થિતિમાન ઊર્જા
દેહલી ઊર્જા
આંતરિક ઊર્જા
સક્રિયકરણ ઊર્જા

72. પ્રથમ ક્રમની એક પ્રક્રિયામાં 75 % પ્રક્રિયકનું વિઘટન 1.386 કલાકમાં થાય છે. આ પ્રક્રિયાનો વેગ-અચળાંક જણાવો.

$1.8 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$2.8 space cross times space 10 to the power of negative 4 end exponent space straight s to the power of negative 1 end exponent$
$17.2 space cross times 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$3.6 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$

73. નીચેના પૈકી કયું સાચું આર્હેનિયસ સમીકરણ છે ?

$straight K space equals space straight A space times space straight e to the power of begin inline style bevelled fraction numerator negative Ea over denominator RT end fraction end style end exponent$
$In space straight K space equals space In space straight A space minus space Ea over RT$
$In space straight K subscript 2 over straight K subscript 1 space equals space Ea over straight R space open parentheses 1 over straight T subscript 1 space minus space 1 over straight T subscript 2 close parentheses$
આપેલ બધા જ

74.

46.06 àª®àª¿àª¨àª¿àªŸ
460.6 àª®àª¿àª¨àª¿àªŸ
23.03 àª®àª¿àª¨àª¿àªŸ
230.5 àª®àª¿àª¨àª¿àªŸ

75.

$3.466 space cross times 10 to the power of negative 3 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 4 end exponent straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 5 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

76.

$fraction numerator 0.346 over denominator straight K end fraction$
$fraction numerator 0.25 over denominator straight K end fraction$
$fraction numerator 0.29 over denominator straight K end fraction$
$fraction numerator 1.38 over denominator straight K end fraction$

$fraction numerator 0.29 over denominator straight K end fraction$

àª®à«‚àª³ àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ = 100% = [R]₀ 25% àªµàªªàª°àª¾àª¶

$therefore space$ àª¬àª¾àª•à«€ 75% = [R]_t

$straight t subscript begin inline style bevelled 1 fourth end style end subscript space equals space fraction numerator 2.303 over denominator straight K end fraction space log space 100 over 75 space equals space fraction numerator 2.303 over denominator straight K end fraction space log space 1.333 space space space space space space equals space fraction numerator 0.29 over denominator straight K end fraction$

àª®à«‚àª³ àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ = 100% = [R]₀ 25% àªµàªªàª°àª¾àª¶

$therefore space$ àª¬àª¾àª•à«€ 75% = [R]_t

77.

15 àª®àª¿àª¨àª¿àªŸ
45 àª®àª¿àª¨àª¿àªŸ
60 àª®àª¿àª¨àª¿àªŸ
30 àª®àª¿àª¨àª¿àªŸ

78.

360 àª®àª¿àª¨àª¿àªŸ
300 àª®àª¿àª¨àª¿àªŸ
398.8 àª®àª¿àª¨àª¿àªŸ
400 àª®àª¿àª¨àª¿àªŸ

79.

$bold N subscript bold 2 bold O subscript bold 5 bold space bold rightwards arrow bold space bold 2 bold NO subscript bold 2 bold space bold plus bold space bold 1 over bold 2 bold O subscript bold 2 bold space$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ $bold t subscript begin inline style bold 1 over bold 2 end style end subscript bold space bold equals bold space bold 24$ àª•àª²àª¾àª• àª›à«‡. 10 àª—à«àª°àª¾àª® N₂O₅ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€ 96 àª•àª²àª¾àª• àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ N₂O₅ àª¨à«‹ àªœàª¥à«àª¥à«‹ àª•à«‡àªŸàª²à«‹ àª¹àª¶à«‡ ?

1.25 àª—à«àª°àª¾àª®
1.77 àª—à«àª°àª¾àª®
0.63 àª—à«àª°àª¾àª®
0.5 àª—à«àª°àª¾àª®

80.

20 àª®àª¿àª¨àª¿àªŸ
40 àª®àª¿àª¨àª¿àªŸ
10 àª®àª¿àª¨àª¿àªŸ
80 àª®àª¿àª¨àª¿àªŸ

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Gujarati JEE Chemistry : રસાયણિક ગતિકી

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