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Gujarati JEE Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

Multiple Choice Questions

141. આપેલ કયા સંયોજન માટે મોલરવાહકતા અને (મોલારિટી)^{^1/2} નો આલેખ સીધી રેખા મળે છે ?

CsCl
NH₄OH
HCOOH
આપેલ ત્રણેય માટે

142. આપેલમાંથી કોની અનંતમંદને તુલ્યવાહકતા સૌથી વધારે છે ?

Rb_(aq)
Cs_(aq)
Na_(aq)
K_(aq)

143. એક પ્રબળ વિદ્યુતવિભાજ્ય માટે C = 0.04 M હોય, ત્યારે $bold capital lambda subscript bold m bold space bold equals bold space bold 250 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent$ છે C = 0.09 M અને હોય ત્યારે $bold capital lambda subscript bold m bold space bold equals bold space bold 200 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent$ છે તો તે વિદ્યુતવિભાજ્ય માટે $straight capital lambda space$ અને $bold capital lambda subscript bold m superscript bold 0$ અનુક્રમે કેટલા હશે ?

550, 265 S cm²mol^-1
500, 350 S cm²mol^-1
340, 450 S cm²mol^-1
450, 365 S cm²mol^-1

144.

bold 1 over bold 3 bold capital lambda to the power of bold 0 subscript bold mAl to the power of bold 3 end subscript bold space bold equals bold space bold 63 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold 1 over bold 2 bold capital lambda to the power of bold 0 subscript bold mMg to the power of bold 2 end subscript bold space bold equals bold space bold 53 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 subscript bold mOH to the power of bold minus end subscript bold space bold equals bold 199 bold. bold 1 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold 1 over bold 2 bold capital lambda to the power of bold 0 bold SO presubscript bold m subscript bold 4 to the power of bold 3 bold minus end exponent bold space bold equals bold space bold 80 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent

સમૂહ-1 માં આપેલ સંયોજન અને સમૂહ-2 આપેલ અનંતમંદને મોલરવાહકતા માટે યોગ્ય વિકલ્પ પસંદ કરો.

(i)-(F), (ii)-(D), (iii)-(H), (iv)-(B)
(i)-(C), (ii)-(D), (iii)-(H), (iv)-(B)
(i)-(F), (ii)-(A), (iii)-(E), (iv)-(G)
(i)-(C), (ii)-(G), (iii)-(A), (iv)-(E)

145. આપેલમાંથી કયા વિકલ્પના બધા જ વિદ્યુતવિભાજ્યોના જલીય દ્વાવણ માટે $bold capital lambda subscript bold m bold space bold rightwards arrow square root of bold C$ ના આલેખનો ઢાળ સમાન હોય છે.
(i) NaCl (ii) NH₄OH (iii) KNO₃ (v) KBr (Vi) HCN (vii) CaCl₂ (viii) FeCl₃

(i), (v), (vi)
(iii), (viii)
(i), (iii), (v)
(ii), (iv), (viii)

146. $bold capital lambda subscript bold m bold space bold equals bold space bold capital lambda to the power of bold 0 subscript bold m bold space bold minus bold space bold A bold times bold C to the power of begin inline style bold 1 over bold 2 end style end exponent$ કયા સયોજનને લાગુ પડે છે ?

NH₄OH
HCOOH
NaCl
HCN

NaCl

147.

$bold capital lambda to the power of bold 0 subscript bold mMg to the power of bold 2 end subscript bold equals bold space bold 106 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 subscript bold mCa to the power of bold 2 to the power of blank end exponent end subscript bold space bold equals bold space bold 119 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold 0 bold space bold comma bold space bold capital lambda to the power of bold 0 subscript bold mCl to the power of bold minus end subscript bold space bold equals bold space bold 76 bold. bold 3 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space$ $bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 bold SO presubscript bold m subscript bold 4 to the power of bold 2 bold minus end exponent bold space bold equals bold space bold 160 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold space$ સમૂહ-1 માં આપેલ સંયોજક અને સમૂહ-2 માં આપેલ અનંતમંદને મોલરવાહકતા માટે યોગ્ય વિકલ્પ પસંદ કરો.

(i)-(F), (ii)-(D), (iii)-(H), (iv)-(B)
(i)-(C), (ii)-(D), (iii)-(H), (iv)-(B)
(i)-(F), (ii)-(A), (iii)-(E), (iv)-(G)
(i)-(C), (ii)-(G), (iii)-(A), (iv)-(E)

148. આપેલમાંથી કયો પદાર્થ અર્ધવાહક છે ?

કાચ
CuO
Cu₂O
ટેફલોન

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Gujarati JEE Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

Multiple Choice Questions

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