àª•àªˆ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¦à«àªµàª¾àª°àª¾ àª¨àª¾àªˆàªŸà«àª°à«‰àªœàª¨ (I) àª‘àª•à«àª¸àª¾àªˆàª¡ àª¬àª¨àª¾àªµà«€ àª¶àª•àª¾àª¯ àª›à«‡ ? from Chemistry p-વિભાગના તત્વો

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Gujarati JEE Chemistry : p-વિભાગના તત્વો

Multiple Choice Questions

141. ICl₃ એ વિદ્યુતવાહકતા દર્શાવે છે કારણ કે વિદ્યુતવિભાજન કરતાં તેનું આયનીકરણ ................. માં થાય છે.

$2 ICl subscript 3 space rightwards harpoon over leftwards harpoon space ICl subscript 4 space plus space ICl subscript 2 to the power of minus$
$2 ICl subscript 3 space rightwards harpoon over leftwards harpoon space ICl subscript 2 space plus space ICl subscript 4 to the power of minus$
$ICl subscript 3 space rightwards harpoon over leftwards harpoon space straight I space plus space 3 Cl to the power of minus$
$2 ICl subscript 3 space rightwards harpoon over leftwards harpoon space straight I space plus space ICl subscript 5 to the power of minus$

142.

àª†àª¯à«‹àª¡à«€àª¨àª¨à«€ àª—àª°àª® àª…àª¨à«‡ àª¸àª¾àª‚àª¦à«Âàª° NaOH àª¸àª¾àª¥à«‡àª¨à«€ àªªà«Âàª°àª•à«Âàª°àª¿àª¯àª¾àª¥à«€ ........... àª®àª³à«‡.

NaI + NaIO₃ + H₂O
NaI + NaIO + O₂
NaI + HIO₃ + H₂OI
NaI + HIO + O₂

143. કયો હેલોજન HNO₃ દ્વારા ઑક્સિડેશન પામે છે ?

Cl₂
Br₂
I₂
F₂

144. 2NaOH + X → Y + H₂O
Y + H₂O + SO₂ → Z સમીકરણોમાં X, Y અને Z નાં સૂત્રો દર્શાવો.

X = SO₂, Y = Na₂SO₃, Z = NaHSO₃
X = SO₂, Y = NaHSO₃, Z = Na₂SO₃
X = SO₃, Y = Na₂SO₃, Z = NaHSO₄
X = SO₂, Y = Na₂SO₃, Z = Na₂SO₄

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145. પેરા-પર આયોડિન ઍસિડ એ ……………. ધરાવે છે.

IO₆^-2આયન
IO₃^- આયન
IO₅^-3 આયન
IO₄^- આયન

146. ............ ની હાજરીમાં આયોડિન પાણીમાં દ્રાવ્ય થાય છે.

KI
Cl₂
Br₂
KBr

147.

àª¨à«€àªšà«‡ àª†àªªà«‡àª² àª«àª•àª°àª¾ àªªàª°àª¥à«€ àªªà«àª°àª¶à«àª¨àª¨à«‹ àªœàªµàª¾àª¬ àª²àª–à«‹:
àªàª• àªœàª¾àª‚àª¬àª²à«€ àª˜àª¨ àªªàª¦àª¾àª°à«àª¥ X àª NH₃ àª¸àª¾àª¥à«‡ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª•àª°à«€ àª®àª‚àª¦ àª¸à«àª«à«‹àªŸàª• àªªàª¦àª¾àª°à«àª¥ Y àª¬àª¨àª¾àªµà«‡ àª›à«‡ àª¤à«‡ àªœàª¾àª‚àª¬àª²à«€ àª°àª‚àª— àª¦à«àª° àª•àª°à«‡ àª›à«‡. X àª¨à«€ H₂àª¸àª¾àª¥à«‡àª¨à«€ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¥à«€ àªàª¸àª¿àª¡ Z àª®àª³à«‡ àª›à«‡. H₃PO₄ àª¨à«€ àª•à«àª·àª¾àª° àª¸àª¾àª¥à«‡àª¨à«€ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¥à«€ àªªàª£ Z àª¬àª¨àª¾àªµà«€ àª¶àª•àª¾àª¯ àª›à«‡.
àªªà«àª°àª¶à«àª¨ : àªœàª¾àª‚àª¬àª²à«€ àª°àª‚àª—àª¨à«‹ àª˜àª¨ àªªàª¦àª¾àª°à«àª¥ àª•àª¯à«‹ àª¹àª¶à«‡ ?

SO₂
Br₂
I₂
Cl₂

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148.

àª•àªˆ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¦à«àªµàª¾àª°àª¾ àª¨àª¾àªˆàªŸà«àª°à«‰àªœàª¨ (I) àª‘àª•à«àª¸àª¾àªˆàª¡ àª¬àª¨àª¾àªµà«€ àª¶àª•àª¾àª¯ àª›à«‡ ?

àªàª®à«‹àª¨àª¿àª¯àª® àª¨àª¾àªˆàªŸà«àª°à«‡àªŸàª¨àª¾ àª‰àª·à«àª®à«€àª¯ àªµàª¿àª˜àªŸàª¨ àª¦à«àªµàª¾àª°àª¾
àªàª®à«‹àª¨àª¿àª¯àª® àª¨àª¾àªˆàªŸà«àª°àª¾àªàªŸàª¨àª¾ àª‰àª·à«àª®à«€àª¯ àªµàª¿àª˜àªŸàª¨ àª¦à«àªµàª¾àª°àª¾
N₂O₄ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€
àª‰àªªàª°àª¨à«€ àª¬àª§à«€ àªœ.

C.

N₂O₄ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€

F₂ àª•àª°àª¤àª¾àª‚ Cl₂ àª¨àª¿àª°à«àª¬àª³ àª‘àª•à«àª¸àª¿àª¡àª¾àªˆàªàª¿àª‚àª— àªàªœàª¨à«àªŸ àª›à«‡. àª¤à«‡àª¥à«€ àª¤à«‡ Naf àª®àª¾àª‚àª¥à«€ F₂ àª¨à«‡ àª¦à«‚àª° àª•àª°à«€ àª¶àª•àª¾àª¤à«‹ àª¨àª¥à«€.

F₂ àª•àª°àª¤àª¾àª‚ Cl₂ àª¨àª¿àª°à«àª¬àª³ àª‘àª•à«àª¸àª¿àª¡àª¾àªˆàªàª¿àª‚àª— àªàªœàª¨à«àªŸ àª›à«‡. àª¤à«‡àª¥à«€ àª¤à«‡ Naf àª®àª¾àª‚àª¥à«€ F₂ àª¨à«‡ àª¦à«‚àª° àª•àª°à«€ àª¶àª•àª¾àª¤à«‹ àª¨àª¥à«€.

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149.

àªœà«àª¯àª¾àª°à«‡ àª¬à«àª²àª¿àªšàª¿àª‚àª— àªªàª¾àªµàª¡àª°àª¨àª¾àª‚ àªœàª²à«€àª¯ àª¦à«àª°àª¾àªµàª¨àª®àª¾àª‚àª¥à«€ CO₂ àªµàª¾àª¯à«àª‚ àªªàª¸àª¾àª° àª•àª°àªµàª¾àª®àª¾àª‚ àª†àªµà«‡ àª›à«‡, àª¤à«àª¯àª¾àª°à«‡ àª¨à«€àªšà«‡àª¨àª¾àª®àª¾àª‚àª¥à«€ àª•àª¯à«‹ àªµàª¾àª¯à« àª‰àª¤à«àªªàª¨à«àª¨ àª¥àª¾àª¯ àª›à«‡ ?

Cl₂
O₂
O₃
Cl₂O

150.

àªªà«‹àªŸà«‡àª¶àª¿àª¯àª® àª¬à«àª°à«‹àª®àª¾àªˆàª¡àª¨àª¾ àª¦à«àª°àª¾àªµàª£àª¨à«€ àª•à«‹àª¨à«€ àª¸àª¾àª¥à«‡ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¥à«€ àª¬à«àª°à«‹àª®àª¿àª¨ àª®à«àª•à«àª¤ àª•àª°à«€ àª¶àª•àª¾àª¯ àª›à«‡ ?

Cl₂ àª¨à«àª‚ àªªàª¾àª£à«€
NOCl
I₂ àª¨à«àª‚ àª¦à«àª°àª¾àªµàª£
KI

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