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Gujarati JEE Mathematics : લક્ષ-સાતત્ય અને વિકલન

Multiple Choice Questions

51.

bold જ ો bold space bold space bold y bold space bold equals bold space bold cot to the power of bold minus bold 1 end exponent open parentheses fraction numerator bold log open parentheses begin display style bold e over bold x to the power of bold 2 end style close parentheses over denominator bold log bold left parenthesis bold ex to the power of bold 2 bold right parenthesis end fraction close parentheses bold space bold plus bold space bold cot to the power of bold minus bold 1 end exponent bold space open parentheses fraction numerator bold log bold left parenthesis bold ex to the power of bold 4 bold right parenthesis over denominator bold log open parentheses begin display style bold e to the power of bold 2 over bold x to the power of bold 2 end style close parentheses end fraction close parentheses bold comma bold space bold ત ો bold space bold dy over bold dx bold space bold equals bold space bold. bold. bold. bold. bold. bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold 0 bold less than bold space bold logx bold space bold less than bold 1 over bold 2

1
-1
2
0

52.

ધારો કે [0,1] માં વિધેય f ના દ્વિતિય વિકલિતનું અસ્તિત્વ છે અને |f"(x)| ≤ 1, ∀ x ∈[0,1]. જો f(0) = f(1) હોય તો, અંતરાલ (0,1) માં

|f'(x)| > 1
|f'(x)|>1
|f''(x)| < 1
|f(x)|<1

53.

bold જ ો bold space bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open curly brackets table row cell bold minus bold x bold minus bold pi over bold 2 bold comma end cell cell bold x bold less-than or slanted equal to bold minus bold pi over bold 2 end cell row cell bold minus bold cos bold space bold x bold comma end cell cell bold minus bold pi over bold 2 bold less than bold x bold less-than or slanted equal to bold 0 end cell row cell bold x bold minus bold 1 bold comma end cell cell bold 0 bold less than bold x bold less-than or slanted equal to bold 1 end cell row cell bold log bold space bold x bold comma end cell cell bold x bold greater than bold 1 end cell end table close bold space bold ત ો bold space

f(x) એ x = $bold minus bold 3 over bold 2$ , 1આગળ વિકલનીય છે.
f(x) એ x = $bold minus bold pi over bold 2$ આગળ સતત છે.
f(x) એ x = 0 આગળ વિકલનીય નથી.
આપેલ તમામ

54. નીચેનામાંથી કયું વિધેય અંતરાલ [-1, 1] માં રોલના પ્રમેયની શરતોનું પાલન કરે છે.

f(x) = [x] + [-x]
f(x) = |x| [x]
f(x) = |x| - |sin x|
$bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open curly brackets table attributes columnalign left end attributes row cell fraction numerator bold sin bold space bold x over denominator bold x end fraction bold comma bold space bold x bold # bold 0 bold space end cell row cell bold 0 bold space bold comma bold space bold x bold space bold equals bold space bold 0 bold space end cell end table close$

55.

જો y = (1+x) (1+x²) (1+x⁴) ... + log (1+x²ⁿ) તો x = 0 આગળની કિંમત ......

1
-1
2
0

Tips: -

y = (1+x) (1+x²) (1+x⁴) ... + log (1+x²ⁿ)

log y = log (1+x)+ log (1+x²) + log (1+x⁴) .... + log (1+x²ⁿ)

વિકલન કરતાં,
$bold 1 over bold y bold space bold dy over bold dx bold space bold equals bold space open square brackets fraction numerator bold 1 over denominator bold 1 bold plus bold x end fraction bold plus fraction numerator bold 2 bold x over denominator bold 1 bold plus bold x to the power of bold 2 end fraction bold plus fraction numerator bold 4 bold x to the power of bold 3 over denominator bold 1 bold plus bold x to the power of bold 3 end fraction bold space bold plus bold space bold. bold. bold. bold plus bold space fraction numerator bold 2 bold nx to the power of bold 2 bold n bold minus bold 1 end exponent over denominator bold left parenthesis bold 1 bold plus bold x bold right parenthesis to the power of bold 2 bold n end exponent end fraction close square brackets bold therefore bold space bold dy over bold dx bold space bold equals bold space bold y bold space open square brackets fraction numerator begin display style bold 1 end style over denominator begin display style bold 1 bold plus bold x end style end fraction bold plus fraction numerator begin display style bold 2 bold x end style over denominator begin display style bold 1 bold plus bold x to the power of bold 2 end style end fraction bold plus fraction numerator begin display style bold 4 bold x to the power of bold 3 end style over denominator begin display style bold 1 bold plus bold x to the power of bold 3 end style end fraction bold space bold plus bold space bold. bold. bold. bold plus bold space fraction numerator begin display style bold 2 bold nx to the power of bold 2 bold n bold minus bold 1 end exponent end style over denominator begin display style bold left parenthesis bold 1 bold plus bold x bold right parenthesis to the power of bold 2 bold n end exponent end style end fraction close square brackets bold space bold આથ ી bold space open parentheses bold dy over bold dx close parentheses subscript bold x bold equals bold 0 end subscript bold space bold equals bold space bold y bold left parenthesis bold 0 bold right parenthesis bold space bold times bold 1 bold space bold equals bold space bold 1$

56.

ધારો કે f : R →R, f(x+y) = f(x) + f(y); ∀ x, y ∈ R. જો f(x) એ x = 0 આગળ વિકલનીય હોય, તો

f એ R પર સતત નથી.
f(x) એ અમુક બિંદું સિવાય વિકલનીય છે.
f(x) એ (a, b)જ્યાં a < 0 < b અંતરાલમાં વિકલનીય હોય.
f(x) = અચળ

57.

f(x) = [x] sin $bold pi$ x, વિધેયનું fનું x = k,k ∈ Z આગળ ડાબી બાજુનું વિકલિત ...... છે.

(-1)^k-1 (k-1) $bold pi$
(-1)^k k $bold pi$
(-1)^k-1 k $bold pi$
(-1)^k (k -1) $bold pi$

58.

bold જ ો bold space bold lim with bold x bold rightwards arrow bold 0 below bold space bold left square bracket bold 1 bold plus bold xlog bold left parenthesis bold 1 bold plus bold b to the power of bold 2 bold right parenthesis bold right square bracket to the power of bold 1 over bold x end exponent bold space bold equals bold space bold 2 bold space bold b bold space bold sin to the power of bold 2 bold space bold theta bold comma bold space bold b bold space bold greater than bold space bold 0 bold space bold અન ે bold space bold theta bold space bold element of bold space bold left square bracket bold minus bold pi bold comma bold pi bold right square bracket bold space bold ત ો bold space bold theta bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold.

$bold plus-or-minus bold pi over bold 2$
$bold plus-or-minus bold pi over bold 4$
$bold plus-or-minus bold pi over bold 3$
$bold plus-or-minus bold pi over bold 6$

59.

જો f(x) = (x+1)(x+2)(x+3)....(x + 100) અને g(x) = f(x) - (f(x))2 તો g(x) = 0 ને

એક ઉકેલ મળે.
ઉકેલ નથી.
બે ઉકેલ મળે.
ઓછામાં ઓછા ત્રણ ઉકેલ મળે.

60.

$bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space bold g bold apostrophe bold left parenthesis bold x bold right parenthesis bold space fraction numerator bold e to the power of begin display style bold a over bold x end style end exponent bold minus bold e to the power of bold minus begin display style bold a over bold x end style end exponent over denominator bold g to the power of begin display style bold a over bold x end style end exponent bold space bold plus bold space bold e to the power of bold minus begin display style bold a over bold x end style end exponent end fraction bold space$ જ્યાં g' એ વિધેય g નું વિકલિત છે તથા સતત વિધેય છે અને a > 0. જો $bold lim with bold x bold rightwards arrow bold 0 below bold space bold f bold left parenthesis bold x bold right parenthesis$ નું અસ્તિત્વ હય તો

g(x) = a₀ + a₁x + a₂x² + ..... + a_nx^-n જ્યાં a_i ∈ R, i = 1,2 ....n તથા a₁ # 0 a_n # 0
g(x) = log (1 + x)
g એવું વિધેય હોય જ્યાં g'(0) = 0
g(x0 = sin x

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Gujarati JEE Mathematics : લક્ષ-સાતત્ય અને વિકલન

Multiple Choice Questions

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