Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Gujarati JEE Mathematics : લક્ષ-સાતત્ય અને વિકલન

Multiple Choice Questions

161. જો y(x) = cos (3 cos^-1x), x∈[-1, 1] x # ± $fraction numerator square root of bold 3 over denominator bold 2 end fraction$ તો $fraction numerator bold 1 over denominator bold y bold left parenthesis bold x bold right parenthesis end fraction bold space open curly brackets bold left parenthesis bold x to the power of bold 2 bold space bold minus bold space bold 1 bold right parenthesis fraction numerator bold d to the power of bold 2 bold y bold left parenthesis bold x bold right parenthesis over denominator bold dx to the power of bold 2 end fraction bold plus bold x fraction numerator bold dy bold left parenthesis bold x bold right parenthesis over denominator bold dx end fraction close curly brackets bold equals bold space bold. bold. bold. bold. bold. bold space$

162.

aની કઈ કિંમત માટે f(x) = x³ + 3(a-7)x² + 3(a² - 9) x - 1 નું સ્થાનીય મહત્તમ મૂલ્ય ધન સંખ્યા માટે મળે ?

a < -3
-1 , a < 1
3 < a < 4
5 < a < 6

163.

જો f'(sin x) < 0 અને f"(sin x) > 0. ∀ x ∈ R, તો g(x) = f(sin x) + f(cos x), x ∈ એ

$open parentheses bold 0 bold comma bold pi over bold 4 close parentheses$ માં ઘટતું વિધેય છે.
$open parentheses bold pi over bold 4 bold apostrophe bold pi over bold 2 close parentheses$ માં વધતું વિધેય છે.
વિધેય g ને x = $bold pi over bold 4$ આગળ સ્થાનીય ન્યુનતમ મળે.
વિધેય g ને x = $bold pi over bold 4$ આગળ સ્થાનીય મહત્તમ મળે.

164.

bold lim with bold n bold rightwards arrow bold infinity below bold space fraction numerator bold minus bold 3 bold n bold space bold plus bold space bold left parenthesis bold minus bold 1 bold right parenthesis to the power of bold n bold space over denominator bold 4 bold n bold space bold minus bold space bold left parenthesis bold minus bold 1 bold right parenthesis to the power of bold n end fraction bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold space

જો n અયુગ્મ સંખ્યા હોય તો $fraction numerator bold minus bold 3 over denominator bold 4 end fraction$
જો n યુગ્મ સંખ્યા હોય તો $fraction numerator bold minus bold 3 over denominator bold 4 end fraction$
$fraction numerator bold minus bold 3 over denominator bold 4 end fraction$
લક્ષનું અસ્તિત્વ નથી.

જો n અયુગ્મ સંખ્યા હોય તો $fraction numerator bold minus bold 3 over denominator bold 4 end fraction$

જો n યુગ્મ સંખ્યા હોય તો $fraction numerator bold minus bold 3 over denominator bold 4 end fraction$

fraction numerator bold minus bold 3 over denominator bold 4 end fraction

Tips: -

bold જ ો bold space bold n bold space bold element of bold space bold N bold space bold ત ો bold space bold lim with bold n bold rightwards arrow bold infinity below bold space fraction numerator bold minus bold 3 bold n bold space bold plus bold space bold left parenthesis bold minus bold 1 bold right parenthesis to the power of bold n bold space over denominator bold 4 bold n bold space bold minus bold space bold left parenthesis bold minus bold 1 bold right parenthesis to the power of bold n end fraction bold space bold equals bold space bold lim with bold n bold rightwards arrow bold infinity below bold space fraction numerator bold minus bold 3 bold plus-or-minus bold space begin display style bold 1 over bold n end style over denominator bold 4 bold plus-or-minus bold space begin display style bold 1 over bold n end style end fraction bold space bold equals bold space fraction numerator bold minus bold 3 over denominator bold 4 end fraction

165.

f(x) એ ત્રણ ઘાતવાળું બહુપદી વિધેય છે, જ્યાં f(0) + 2 = 0 અને f"'(0) = 6. જો f(x) = 0 નાં ત્રણેય બીજ ધન પૂર્ણાંક હોય, તો

f'(1) = 0
2f(0) + f"(0) = 0
2f(0) + f"(0) = 2
f(2) = 0

166.

h ઉંચાઈ તથા અર્ધશીર્ષકોણ વાળા શંકુમાં અંતર્ગત મહત્તમ ઘનફળવાળા નળકારનું ઘનફળ ..... છે.

$bold 4 over bold 27 bold space bold πh to the power of bold 3 bold space bold tan to the power of bold 3 bold alpha bold space$
$bold 1 over bold 27 bold space bold h to the power of bold 3 bold space bold tan to the power of bold 3 bold space bold alpha$
$bold 4 over bold 27 bold space bold h to the power of bold 2 bold space bold tan to the power of bold 2 bold space bold alpha$
$bold 4 bold πh to the power of bold 3 bold space bold tan to the power of bold 3 bold space bold alpha bold space$