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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

31. જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold 1 bold x cell bold x to the power of bold 2 end cell row bold x cell bold x to the power of bold 2 end cell bold 1 row cell bold x to the power of bold 2 end cell bold 1 bold x end table close vertical bar$ હોય તો $bold f open parentheses root index bold 3 of bold 3 close parentheses$ = ...... .

4
2
-2
-4

32.

જો સમીકરણો a(y+z) x; b (z+x) = y, c(x+y) = z નો અનન્ય ઉકેલ મળે, તો $fraction numerator bold 1 over denominator bold 1 bold plus bold a end fraction bold plus fraction numerator bold 1 over denominator bold 1 bold plus bold b end fraction bold plus fraction numerator bold 1 over denominator bold a bold plus bold c end fraction bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold space bold left parenthesis bold x bold space bold greater than bold space bold 0 bold comma bold space bold y bold space bold greater than bold space bold 0 bold comma bold space bold z bold space bold greater than bold space bold 0 bold right parenthesis$

-2
-2
1
2

33. જો $bold D bold space bold equals bold space open vertical bar table row bold 1 bold cosθ bold 1 row cell bold minus bold cosθ end cell bold 1 bold cosθ row cell bold minus bold 1 end cell bold cosθ bold 1 end table close vertical bar$ તો D .......અંતરાલમાં છે.

[1, 4]
[0, 2]
[2, 4]
[0, 4]

34. જો $open vertical bar table row cell bold y bold plus bold z end cell cell bold z bold plus bold x end cell cell bold x bold plus bold y end cell row cell bold x bold plus bold y end cell cell bold y bold plus bold z end cell cell bold z bold plus bold x end cell row cell bold z bold plus bold x end cell cell bold x bold plus bold y end cell cell bold y bold plus bold z end cell end table close vertical bar bold space bold equals bold space bold k bold space open vertical bar table row bold x bold y bold z row bold z bold x bold y row bold y bold z bold x end table close vertical bar$ તો k = ......... (x=y=zનથી, x+y+x ≠0)

-4
2
1
4

35. $open vertical bar table row bold a bold b bold c row bold x bold y bold z row bold p bold q bold r end table close vertical bar bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold space bold.$

$open vertical bar table row bold y bold b bold q row bold x bold a bold p row bold z bold c bold r end table close vertical bar$
$open vertical bar table row bold y bold q bold b row bold x bold p bold a row bold z bold c bold r end table close vertical bar$
$open vertical bar table row bold b bold y bold q row bold a bold p bold x row bold c bold z bold r end table close vertical bar$
આપેલ પૈકી એક પણ નહી

36. $bold D bold space bold equals bold space open vertical bar table row bold bc cell bold a to the power of bold 2 end cell cell bold a to the power of bold 2 end cell row cell bold b to the power of bold 2 end cell bold ca cell bold b to the power of bold 2 end cell row cell bold c to the power of bold 2 end cell cell bold c to the power of bold 2 end cell bold ab end table close vertical bar bold space bold અન ે bold space bold D bold apostrophe bold space bold equals bold space open vertical bar table row bold bc bold ab bold ca row bold ab bold ca bold bc row bold ca bold bc bold ab end table close vertical bar$ તો ........ .

D = D'
aD + bD' = 0
bD + aD' = 0
D + D' = 0

37. જો $bold D bold space bold equals bold space open vertical bar table row bold 1 cell bold 3 bold cosθ end cell bold 1 row cell bold sin bold space bold theta end cell bold 1 cell bold 3 bold cosθ end cell row bold 1 bold sinθ bold 1 end table close vertical bar$ તો D નું મહત્તમ મૂલ્ય ........ છે.

38. જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold 1 bold x cell bold x bold plus bold 1 end cell row cell bold 2 bold x end cell cell bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis end cell cell bold left parenthesis bold x bold plus bold 1 bold right parenthesis bold x end cell row cell bold 3 bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis end cell cell bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis bold left parenthesis bold x bold minus bold 2 bold right parenthesis end cell cell bold x bold left parenthesis bold x bold plus bold 1 bold right parenthesis bold left parenthesis bold x bold minus bold 1 bold right parenthesis end cell end table close vertical bar$ તો f(100) = .......

1
0
100
-100

Tips: -

bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis bold space bold left parenthesis bold x bold plus bold 1 bold right parenthesis bold space open vertical bar table row bold 1 bold 1 bold 1 row cell bold 2 bold x end cell cell bold x bold minus bold 1 end cell bold x row cell bold 3 bold x end cell cell bold x bold minus bold 2 end cell bold x end table close vertical bar bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold C subscript bold 2 bold space open parentheses bold 1 over bold x close parentheses bold comma bold C subscript bold 3 bold space open parentheses fraction numerator bold 1 over denominator bold x bold plus bold 1 end fraction close parentheses bold comma bold space bold R subscript bold 3 bold space open parentheses fraction numerator bold 1 over denominator bold x bold minus bold 1 end fraction close parentheses bold space bold space bold space bold space bold space bold space bold equals bold space bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis bold space bold left parenthesis bold x bold plus bold 1 bold right parenthesis bold space open vertical bar table row bold 0 bold 0 bold 1 row cell bold x bold plus bold 1 end cell cell bold minus bold 1 end cell bold x row cell bold 2 bold left parenthesis bold x bold plus bold 1 bold right parenthesis end cell cell bold minus bold 1 end cell bold x end table close vertical bar bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold C subscript bold 21 bold space bold left parenthesis bold minus bold 1 bold right parenthesis bold comma bold space bold C subscript bold 32 bold left parenthesis bold minus bold 1 bold right parenthesis bold space bold space bold space bold space bold space bold space bold equals bold space bold minus bold space bold x bold left parenthesis bold x bold minus bold 1 bold right parenthesis bold space bold left parenthesis bold x bold plus bold 1 bold right parenthesis to the power of bold 2 bold space open vertical bar table row bold 0 bold 0 bold 1 row bold 1 bold 1 bold x row bold 2 bold 2 bold x end table close vertical bar bold space bold equals bold space bold 0 bold space bold therefore bold space bold f bold left parenthesis bold 100 bold right parenthesis bold space bold equals bold space bold 0 bold space

39. જો $open vertical bar table row cell bold 1 bold plus bold x end cell bold 1 bold 1 row bold 1 cell bold 1 bold plus bold x end cell bold 1 row bold 1 bold 1 cell bold 1 bold plus bold x end cell end table close vertical bar bold space bold equals bold space bold 0 bold comma bold space$ તો = ........ .

0, 3
0, ± 3
0, -3
આપેલ પૈકી એક પણ નહી

40.

સમીકરણો 2x + 3y + 5 = 0, x + ky + 5 = 0 અને kx - 12y - 14 = 0 સુસંગત હોય તો k = ....... .

$bold 6 bold comma bold space bold 17 over bold 5$
$bold minus bold 2 bold comma bold space bold 12 over bold 5$
$bold minus bold 6 bold comma bold space bold 17 over bold 5$
$bold minus bold 6 bold comma bold minus bold 17 over bold 5$

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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

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