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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

71.

bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold x bold 1 bold 1 row bold 1 bold x bold 1 row bold 1 bold 1 bold x end table close vertical bar bold space bold ત ો bold space table row bold 1 row bold integral row bold 0 end table bold f bold left parenthesis bold x bold right parenthesis bold dx bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold.

$fraction numerator bold minus bold 3 over denominator bold 4 end fraction$
$bold 1 over bold 4$
$bold 2 over bold 3$
$bold 3 over bold 4$

72.

જો a,b,c એ સ્વરિત શ્રેણીના અનુક્રમે p માં, r માં પદ હોય તો $open vertical bar table row bold bc bold ca bold ab row bold p bold q bold r row bold 1 bold 1 bold 1 end table close vertical bar$ નું મુલ્ય ..... છે.

0
pqr
abc
એક પણ નહિ

73.

જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold 1 bold cosx row bold cosx bold 1 end table close vertical bar bold comma bold space bold ત ો bold space table row cell bold pi over bold 2 end cell row bold integral row cell fraction numerator bold minus bold pi over denominator bold 2 end fraction end cell end table bold f bold left parenthesis bold x bold right parenthesis bold dx bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold.$

$bold pi over bold 2 bold space$
$bold pi$
$bold space bold 2 bold pi$
2

74.

open vertical bar table row cell bold left parenthesis bold b bold plus bold c bold right parenthesis to the power of bold 2 end cell cell bold a to the power of bold 2 end cell cell bold a to the power of bold 2 end cell row cell bold b to the power of bold 2 end cell cell bold left parenthesis bold c bold plus bold a bold right parenthesis to the power of bold 2 end cell cell bold b to the power of bold 2 end cell row cell bold c to the power of bold 2 end cell cell bold c to the power of bold 2 end cell cell bold left parenthesis bold a bold plus bold b bold right parenthesis to the power of bold 2 end cell end table close vertical bar bold space bold equals bold space bold k bold space bold abc bold left parenthesis bold a bold plus bold b bold plus bold c bold right parenthesis to the power of bold 3 bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold.

-1
1
-2
2

75.

સમીકરણો (x + 1)x + 8y = 4k અને kx + (k + 3)y = 3k - 1 નો ઉકેલ મળે નહિ, તો k = ......

k ∈ R
1
2
3

76.

જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold x cell bold e to the power of bold x to the power of bold 4 end cell bold cosx row cell bold cosec bold space bold x end cell bold 3 bold secx row bold cotx cell bold x to the power of bold 2 end cell bold 7 end table close vertical bar bold space bold ત ો bold space table row cell bold pi over bold 2 end cell row bold integral row cell fraction numerator bold minus bold pi over denominator bold 2 end fraction end cell end table bold f bold left parenthesis bold x bold right parenthesis bold space bold dx bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold.$

0
34
$bold 1 bold equals bold minus bold pi over bold 2$
$bold 5 bold e to the power of bold pi$

77.

open vertical bar table row bold x cell bold minus bold 6 end cell cell bold minus bold 1 end cell row bold 2 cell bold minus bold 3 bold x end cell cell bold x bold minus bold 3 end cell row cell bold minus bold 3 end cell cell bold 2 bold x end cell cell bold x bold plus bold 2 end cell end table close vertical bar bold space bold equals bold space bold 0

3 અથવા 2 અથવા 1
-3 અથવા 2 અથવા 1
-3 અથવા - 2 અથવા 1
-3 અથવા 2 અથવા -1

78.

જો α, β અને γ એ સમીકરણ x³ + px + q = 0 નાં બીજ હોય, તો નું મૂલ્ય .......... છે.

3pq
p² = 2q
p + q
p - q

p - q

Tips: -

$open vertical bar table row bold alpha cell bold minus bold beta end cell bold 0 row bold 0 bold beta cell bold minus bold gamma end cell row bold 1 bold 1 cell bold 1 bold plus bold gamma end cell end table close vertical bar bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold R subscript bold 21 bold left parenthesis bold minus bold 1 bold right parenthesis bold comma bold space bold R subscript bold 32 bold left parenthesis bold minus bold 1 bold right parenthesis$

= α[β + βγ + γ] + βγ
=
αβ + αβγ + αγ + βγ

અહીં, α, β અને γ એ સમીકરણ x3 + px + q = 0 નાં બીજ હોવાથી αβ + βγ + αγ = p અને αβγ = -q

D = -q + p

79. જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row cell bold x to the power of bold 5 end cell cell bold sin to the power of bold 2 bold x end cell cell bold 3 to the power of bold x to the power of bold 4 end cell row cell bold tan to the power of bold 3 bold x end cell bold 1 cell bold sec to the power of bold 2 bold x end cell row cell bold minus bold sin to the power of bold 5 bold x end cell cell bold x to the power of bold 6 end cell bold 5 end table close vertical bar bold space bold ત ો bold space table row bold pi row bold integral row cell bold minus bold pi end cell end table bold f bold left parenthesis bold x bold right parenthesis bold dx bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold.$

0
1
2
-2

80.

જો y = -9 એ આપેલ સમીકરણનું એક બીજ છે, તો $open vertical bar table row bold y bold 3 bold 7 row bold 2 bold y bold 2 row bold 7 bold 6 bold y end table close vertical bar$ નાં બીજાં બીજ ........ છે.

-2 અને 7
2 અને 7
-2 અને -7
2 અને -7

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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

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